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Leya [2.2K]
4 years ago
11

Consider the insoluble compound cobalt(II) hydroxide , Co(OH)2 . The cobalt(II) ion also forms a complex with ammonia . Write a

balanced net ionic equation to show why the solubility of Co(OH)2 (s) increases in the presence of ammonia and calculate the equilibrium constant for this reaction.
Chemistry
1 answer:
Nuetrik [128]4 years ago
7 0

Answer:

4.56×10^-10

Explanation:

Co(OH)2(s)<------->Co^2+(aq) + 2OH^-(aq)

Co^2+(aq) + 6NH3(aq) ---------->[Co(NH3)6]^2+(aq)

Overall equation:

Co(OH)2(s)+ 6NH3(aq) ---------->[Co(NH3)6]^2+(aq) + 2OH^-(aq)

The increased solubility of the cobalt salt in the presence of ammonia is as a result of the formation of the hexammine cobalt II complex shown above.

Knet= Ksp×Kf

Ksp of Co(OH)2= 5.92 × 10^-15.

Kf= 7.7 x 10^4

Knet= 5.92 × 10^-15 × 7.7 x 10^4

Knet= 4.56×10^-10

Note Knet is the equilibrium constant of the overall reaction.

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Approximately 0.0972 g of carbon dioxide gas can be dissolved in 100 mL of water at 40°C expressed in terms of parts per million
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Answer:

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Explanation:

Percent (parts per hundred - pph), parts per million & parts per billion are ratios of a component of interest divided by total mix of several components.

That is, given 28%, this says 28/100, or 28ppm says 28/10⁶, or 28ppb says 28/10⁹.

To convert from the given (=> any of the three concentration ratios) simply multiply (X) where you wish to go.

Examples:

  • Convert 35% to ppm and ppb
  • 35% = (35/100) x 10⁶ppm = 3.5 x 10⁵ ppm
  • _______________________________
  • Convert 43 ppm to %
  • 43 ppm = (43/10⁶) x 100% = 4.3 x 10³%
  • ______________________________
  • Convert 81 ppb to ppm
  • 81 ppb = (81/10⁹) x 10⁶ppm = 8.1 x 10⁻² ppm

Notice how each 'Given' is expressed as a ratio of amount/100 (given pph or %),  or amount/10⁶ (given ppm) or amount/10⁹ (given ppb). All you need to do here is multiply by where you want to go.

=> Given % = (amount/100) x 10⁶ => ppm

=> Given ppm = (amount/10⁶) x 100 => %, or pph

=> Given ppb = (amount/10⁹) x 10⁶ => ppm

Given ratio x 100 = %, or x 10⁶ => ppm or x 10⁹ => ppb

Your Problem:

Given = (0.0972g/100g) x 10⁶ppm = 972 ppm

or, if you wish ppb => (0.0972g/100g) x 10⁹ppb = 972,000 ppb

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