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Advocard [28]
3 years ago
6

Dianne's teacher has a chunk of dry ice for the class to look at. Dry ice is a kind of frozen gas—it is very cold. The teacher w

arns her class not to touch it. When Dianne holds her hand near it, it feels like the dry ice is radiating cold. What is really happening?
A) Heat energy from Dianne's hand is being transferred to the dry ice even though she is not touching it.
B) Chemicals in the dry ice are tricking Diane's nerves into thinking she feels cold.
C) Cold energy from the dry ice is being transferred to Diane's hand even though she is not touching it.
D) Small pieces of the dry ice are breaking off and hitting Diane's hand, making it feel cold.
Physics
2 answers:
Gelneren [198K]3 years ago
4 0
The answer is A. Hope this helps you with your work.
Lera25 [3.4K]3 years ago
3 0

Answer:

A) Heat energy from Dianne's hand is being transferred to the dry ice even though she is not touching it.

Explanation:

In this example, we learn that Dianne feels cold when she holds her hand close to the dry ice. In fact, Dianne feels as it the cold is moving from the dry ice to her hand. However, this is not what is happening. Changes in temperature occur when heat is transferred from a warm body to a colder one. Therefore, what is actually occurring is that heat energy from Dianne's hand is being transferred to the dry ice even though she is not touching it, and this makes her feel cold.

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a tank circuit contains a capacitor and an inductor that produce 30 of reactance at the resonant frequency. the inductor has a q
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The total circuit current at the resonant frequency is 0.61 amps

What is a LC Circuit?

  • A capacitor and an inductor, denoted by the letters "C" and "L," respectively, make up an LC circuit, also referred to as a tank circuit, a tuned circuit, or a resonant circuit.
  • These circuits are used to create signals at particular frequencies or to receive signals from more complicated signals at particular frequencies.

Q =15 = (wL)/R

wL = 30 ohms = Xl

R = 2 ohms

Zs = R + jXl = 2 +j30 ohms where Zs is the series LR impedance

| Zs | = 30.07 <86.2° ohms

Xc = 1/(wC) = 30 ohms

The impedance of the LC circuit is found from:

Zp = (Zs)(-jXc)/( Zs -jXc)

Zp = (2+j30)(-j30)/(2 + j30-j30) = (900 -j60)2 = 450 -j30 = 451 < -3.81°

I capacitor = 277/-j30 = j9.23 amps

I Zs = 277/(2 +j30) = (554 - j8,310)/904 = 0.61 - j9.19 amps

I net = I cap + I Zs = 0.61 + j0.04 amps = 0.61 < 3.75° amps

Hence, the total circuit current at the resonant frequency is 0.61 amps

To learn more about LC Circuit from the given link

brainly.com/question/29383434

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Answer:

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Explanation:

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