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xeze [42]
3 years ago
13

No tengo pregunta jajaja

Chemistry
2 answers:
masha68 [24]3 years ago
8 0

Answer:

--

------Explanation:

Hoochie [10]3 years ago
5 0

Answer:

a pues gracias por los puntos

Explanation:

.......:)

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Realice una historieta que resuma su comprensión acerca de la teoría atómica y los diferentes modelos atomicos que se
Tomtit [17]

Respuesta:

Los modelo atómicos han permitido representar el modo de funcionamiento de los átomos. A lo largo de la historia han surgido un numero de modelos atómicos diferentes incluyendo los modelos de Bohr, Thomson, Rutherford, Sommerfeld, Dalton y Schrödinger.

Explicación:

El modelo atómico propuesto por John Dalton (1808) demostró que las sustancias químicas reaccionan en proporciones fijas y cómo mediante su combinación se producen elementos diferentes. Dalton fue el primero en postular la existencia de elementos indivisibles llamados átomos. A continuación, Thomson (1904) desarrolló un modelo en el cual el átomo estaba compuesto por protones con carga positiva y electrones con carga negativa los cuales se incrustaban uniformemente dentro de este átomo, asemejándose a las pasas de uva de un budín. En 1911, Ernest Rutherford desarrolló un nuevo modelo donde la masa principal del átomo tenía carga positiva y se localizaban en el núcleo, mientras que los electrones con carga negativa se posicionaban en la región externa del átomo. Subsecuentemente, Niels Bohr (1913) represento el funcionamiento del átomo de hidrógeno mediante un protón inmóvil en el núcleo atómico y un electrón girando a su alrededor. El modelo atómico de Sommerfeld permitió generalizar el diagrama de Bohr a otros tipos de átomos mas allá del Hidrógeno, incluyendo diferentes niveles energéticos para cada átomo particular. El modelo de Schrödinger​ (1926) permitió corregir aquellas discordancias surgidas del modelo atómico de Bohr. Schrödinger incluyó diferentes niveles y subniveles de energía a los electrones e incorporó órbitas elípticas a su movimiento, con lo cual permitiendo predecir los efectos relativos de los campos magnético y eléctrico sobre el movimiento de los electrones.

4 0
3 years ago
The mass of a substance is 27.46 g and its volume is 3.42 mL. What is the density of the substance? (hint: density = mass ÷ volu
marin [14]

Answer:

<h2>8.03 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question we have

density =  \frac{27.46}{3.42}  \\  = 8.029239

We have the final answer

<h3>8.03 g/mL</h3>

Hope this helps you

7 0
3 years ago
Read 2 more answers
What is the value of the σ∗1s mo wave function at the nodal plane?
Leona [35]

Answer:

There is None

Explanation:

This is because it is a derived function dependent on other factors.

5 0
3 years ago
Read 2 more answers
Which element has 16 protons in its nucleus?<br> neon<br> oxygen<br> sodium<br> sulfur
Assoli18 [71]

Answer: Sulfur

Explanation: Sulfur has 16 protons, silicon has 14 protons, and gold has 79 protons.

6 0
3 years ago
Consider 2.4 moles of a gas contained in a 4.0 L bulb at a constant temperature of 32°C. This bulb is connected to an evacuated
Luden [163]

Complete Question

The complete question is shown on the first uploaded image

Answer

a

As the valve is opened , the gas will flow into the empty container until the both containers have the same pressure

b

\Delta H = 0\ , \Delta E = 0 , q= 0 , w= 0

c

The driving force for this process is the increase in entropy this is because the movement of the internal energy of the gas into a larger volume, what this does is that it increases the amount of disorder(entropy).

Explanation

In order to obtain the parameter in the part B of the question we are first obtain the initial pressure, using the ideal gas equation  

                      P = \frac{nRT}{V}

                     P = \frac{(2.4mol)(0.0821\frac{1 atm}{K \cdot \ mol} )}{4.0L}

                         P =15 \ atm

The next thing is to obtain the new pressure of the gas , using boyle's law

              P_1V_1 = P_2V_2

                  P_2 = \frac{P_1 V_1}{V_2}

                  P_2 = \frac{(15 \ atm)(4.0L)}{24.0 L}

                  P_2 = 2.5 \ atm    

Since the this process is isothermal , the change in heat is equal to zero

                      i.e  q = 0 J

  The workdone to move  the gas to the other container is zero because the  the pressure at this second container is zero due to the fact that it is a vacuum

    i.e  w = -P_{external} \Delta V

              =-(0 \ atm) (24.0 - 4.0L)

              = 0L \cdot atm

  Since the change in heat is zero and the workdone is zero then the change in internal energy is equal to 0

     This is because the change in internal energy is equal to a summation of change in heat and the workdone

                i.e \Delta E = q + w

                            = 0J

Generally the change in enthalpy is mathematically represented as

                \Delta H = n C_p \Delta T

Since the temperature is zero this means that the change in temperature is zero , substituting this value for change in temperature into the equation for  change in enthalpy

           \Delta H = n C_p (0)

                   = 0J

 

7 0
4 years ago
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