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xeze [42]
3 years ago
13

No tengo pregunta jajaja

Chemistry
2 answers:
masha68 [24]3 years ago
8 0

Answer:

--

------Explanation:

Hoochie [10]3 years ago
5 0

Answer:

a pues gracias por los puntos

Explanation:

.......:)

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If he(g) has an average kinetic energy of 8750 j/mol under certain conditions, what is the root mean square speed of cl2(g) mole
saw5 [17]
<span>The root mean square speed is given by V_rms = âšRT/M where r, t, and m are the rate constant, temperature and molar mass the gas Average molar kinetic energy of the gas E = 1/2 M * (V_rms)^2 = 8750 ms/1 So (V_rms)^2 = (2 * 8750) / M Molar mass of 2 chlorine atoms in kg is 2 * 35 * 10^(-3) Hence we have (V_rms)^2 = (2 * 8750)/ (2 * 35 * 10^(-3)) (V_rms)^2 = 8750/0.035 = 250000 So V_rms = âš 250000 = 500</span>
5 0
3 years ago
Read 2 more answers
An unknown liquid has a vapor pressure of 88 mmhg at 45°c and 39 mmhg at 25°c. What is its heat of vaporization?
Elis [28]

The relation between vapour pressure , enthalpy of vapourisation and temperature is

ln(\frac{P1}{P2} ) = \frac{deltaH}{R} (\frac{1}{T2} - \frac{1}{T1})

ln (88/ 39) = DeltaH / 8.314 (1 / 318 - 1 / 298)

0.814 = DeltaH / 8.314 (2.11 X 10^-4 )

DeltaH = -32.07 kJ


6 0
3 years ago
7. What must you do before you make a hypothesis?
almond37 [142]

Answer:

Ask a question?

Explanation:

look at the scientific method uwu

6 0
3 years ago
You want to minimize an objects thermal energy loss on a cold day. How does heat energy transfer affect thermal energy loss?
san4es73 [151]

Answer:

4- A material that transfers heat energy more easily than another material will experience a greater rate of thermal energy loss than an object that does not transfer heat energy easily.

Explanation:

Thermal energy loss has to do with loss of heat energy by a body to another body or its environment. The aim of the process is usually the attainment of thermal equilibrium between the body and its environment.

On a cold day, a material that transfers thermal energy more easily will loose thermal energy faster than an object that does not transfer thermal energy. The rate of heat transfer of a body determines its rate of loss of thermal energy.

6 0
3 years ago
What is the empirical formula for a compound that is 29.44\% calcium, 23.55% sulfur, and 47.01% oxygen? This compound is a commo
PSYCHO15rus [73]

Answer:

Empirical formula is CaSO₄.

Explanation:

Given data:

Percentage of calcium =29.44%

Percentage of sulfur = 23.55%

Percentage of oxygen = 47.01%

Empirical formula = ?

Solution:

Number of gram atoms of Ca = 29.44 / 40 = 0.74

Number of gram atoms of S = 23.55 / 32 = 0.74

Number of gram atoms of O = 47.01 / 16 = 3

Atomic ratio:

            Ca                      :        S                :         O

           0.74/0.74           :     0.74/0.74      :       3/0.74

               1                     :          1              :          4

Ca : S : O = 1 : 1 : 4

Empirical formula is CaSO₄.

3 0
3 years ago
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