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Vadim26 [7]
2 years ago
9

A chemist prepares a solution of potassium dichromate by measuring out of potassium dichromate into a volumetric flask and filli

ng the flask to the mark with water. Calculate the concentration in of the chemist's potassium dichromate solution. Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
riadik2000 [5.3K]2 years ago
4 0

Answer:

0.297 mol/L

Explanation:

<em>A chemist prepares a solution of potassium dichromate by measuring out 13.1 g of potassium dichromate into a 150 mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's potassium dichromate solution. Be sure your answer has the correct number of significant digits.</em>

<em />

Step 1: Calculate the moles corresponding to 13.1 g of potassium dichromate

The molar mass of potassium dichromate is 294.19 g/mol.

13.1 g × (1 mol/294.19 g) = 0.0445 mol

Step 2: Convert the volume of solution to L

We will use the relationship 1 L = 1000 mL.

150 mL × (1 L/1000 mL) = 0.150 L

Step 3: Calculate the concentration of the solution in mol/L

C = 0.0445 mol/0.150 L = 0.297 mol/L

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If 24.1 g of sodium hydroxide react with 22.0 g of hydrochloric acid to form 35.3g
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Answer:

10.85 g of H2O.

Explanation:

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Next, we shall determine the mass of NaOH that reacted and the mass of H2O produced from the balanced equation.

These can be obtained as illustrated below:

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Summary:

From the balanced equation above,

40 g of NaOH reacted to produce 18 g of H2O.

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From the balanced equation above,

40 g of NaOH reacted to produce 18 g of H2O.

Therefore, 24.1 g of NaOH will react to produce = (24.1 × 18)/40 = 10.85 g of H2O.

Therefore, 10.85 g of H2O were produced from the reaction.

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\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}   ....(1)

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Given mass of potassium chlorate = 93.3 g

Molar mass of potassium chlorate = 122.55 g/mol

Putting values in above equation, we get:

\text{Moles of potassium chlorate}=\frac{93.3g}{122.55g/mol}=0.761mol

For the given chemical reaction:

10KClO_3+12P\rightarrow 3P_4O_{10}+10KCl

Red phosphorus is given in excess . So, it is considered as an excess reagent and potassium chlorate is considered as a limiting reagent.

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10 moles of potassium chlorate reacts with 3 moles of tetraphosphorus decaoxide

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Moles of tetraphosphorus decaoxide = 0.2283 moles

Putting values in equation 1, we get:

0.2283mol=\frac{\text{Mass of tetraphosphorus decaoxide}}{283.886g/mol}\\\\\text{Mass of tetraphosphorus decaoxide}=64.81g

Hence, the mass of tetraphosphorus decaoxide formed is 64.81g

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