Thomson experiment he calculated the charge to mass ratio just be passing the fundamental charge through a tube
He calculated the charge to mass ratio just by finding the deflection of charge while it is passing through the constant electric field
so here we will use the deflection as following
let say it passes the field of length "L"
so here we have
now in the same time if it deflect by some distance
now by solving this equation we can find e/m ratio
so here correct answer will be
the electron's charge-to-mass ratio
Answer: 0.25 m/s
Explanation: Speed = wavelengt · frequency
v = λf and frequency is 1/period f = 1/T
Then v = λ/T = 5 m / 20 s = 0.25 m/s
Answer:
we have τ = I * α as the rotational equation of motion
and we also have τ = F * r
so the torque τ = 5* 0.16 Nm = 0.8 Nm
from your plot of θ vs T^2 , calculate the slope of the line
this slope will be angular acceleration α.
Then you get I = τ/α
Explanation:
8.6 cm
Explanation:
Step 1:
In this we have to find the focal length of converging lens.
To find focal length we have,
where u = Object distance
v= Image distance
f = Focal length
Step 2:
(1/f) = 0.116
f = 1/0.116
f = 8.6 cm
Explanation:
To find the average of these numbers, we just have to add the three numbers together and divide by 3.
- 2.07 + 0. 74 + 1.33 = 4.14. 4.14 / 3 = 1.38
- 1.09 + 1.40 + 0.31 = 2.8. 2.8 / 3 ≈ 9.3333333/ 9 1/3
- 0.95 + 1.61 + 0.56 = 3.12 / 3 = 1.04
- 0.81 + 1.89 + 1.08 = 3.78 / 3 = 1.26
