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AVprozaik [17]
3 years ago
13

Solve for x, and find the length for each Segment

Mathematics
1 answer:
stepan [7]3 years ago
6 0

If AB = BC then you can solve for x which might a good first step. From the givens and the way the diagram is marked, you have

AB = BC

x + 6 = 2x + 12 This is an impossible condition. Using 3x - 31 doesn't help very much

x + 6 + 2x + 12 = 3x - 31

3x + 18 = 3x - 31 From which (if you subtract 3x from both sides

18 = - 31 which never going to be true.

Let's go back to AB = BC

x + 6 = 2x + 12 Subtract x from both sides.

6 = 2x - x + 12

6 = x + 12 Subtract 12 from both sides.

6 - 12 = x

x = - 6

When you check this result, you get

x + 6 = -6 + 6 = 0

2x + 12 = 2*-6 + 12 = 0

X = -6

AB = 0

BC = 0

AC = 0


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Assume that when Human Resource managers are randomly selected, 62% say job applicants should follow up within two weeks. If 25
Alenkinab [10]

Using the binomial distribution, it is found that there is a 38% probability that exactly 18 of them say job applicants should follow up within two weeks.

<h3>How to find that a given condition can be modelled by binomial distribution?</h3>

Binomial distributions consists of n independent Bernoulli trials.

Bernoulli trials are those trials that end up randomly either on success (with probability p) or on failures( with probability 1- p = q (say))

The probability that out of n trials, there'd be x successes is given by

P(X =x) = \: ^nC_xp^x(1-p)^{n-x}

Binomial probability distribution  

P(X =x) = \: ^nC_xp^x(1-p)^{n-x}

The parameters are:

n is the number of trials.

x is the number of successes.

p is the probability of success on a single trial.

In this problem:

62% say job applicants should follow up within two weeks, p = 0.62

25 managers are selected, n = 25

The probability that exactly 18 of them say job applicants should follow up within two weeks is P ( X = 18)

P( X > 18) = 1 -  ( X = 18)

= 1 - 0.62

= 0.38

38 % probability that exactly 18 of them say job applicants should follow up within two weeks.

Learn more about binomial distribution here:

brainly.com/question/13609688

#SPJ1

8 0
2 years ago
A menu list 3 appetizers 4 meals 2 drinks and 2 dessert a dinner consists of 1 of each of these 4 items how many different dinne
e-lub [12.9K]

Answer:

2.75

Step-by-step explanation:

8 0
3 years ago
Which equation could match the table?
DochEvi [55]

Answer:

y=2x+3

Step-by-step explanation:

in third line x = 0 y=2×0+3 =3

5 0
2 years ago
Read 2 more answers
What is the answer to my problem
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Please provide more context for our brains to understand your problem (: thank you!
7 0
3 years ago
a team of 10 players is to be selected from a class of 6 girls and 7 boys. match each scenario to its probability
mars1129 [50]

Step-by-step explanation:

The selection of r objects out of n is done in

many ways.

The total number of selections 10 that we can make from 6+7=13 students is  

thus, the sample space of the experiment is 286

A.  

"The probability that a randomly chosen team includes all 6 girls in the class."

total number of group of 10 which include all girls is C(7, 4), because the girls are fixed, and the remaining 4 is to be completed from the 7 boys, which can be done in C(7, 4) many ways.

P(all 6 girls chosen)=35/286=0.12

B.

"The probability that a randomly chosen team has 3 girls and 7 boys."

with the same logic as in A, the number of groups were all 7 boys are in, is  

so the probability is 20/286=0.07

C.

"The probability that a randomly chosen team has either 4 or 6 boys."

case 1: the team has 4 boys and 6 girls

this was already calculated in part A, it is 0.12.

case 2, the team has 6 boys and 4 girls.

there C(7, 6)*C(6, 4) ,many ways of doing this, because any selection of the boys which can be done in C(7, 6) ways, can be combined with any selection of the girls.  

the probability is 105/286=0.367

since  case 1 and case 2 are disjoint, that is either one or the other happen, then we add the probabilities:

0.12+0.367=0.487 (approximately = 0.49)

D.

"The probability that a randomly chosen team has 5 girls and 5 boys."

selecting 5 boys and 5 girls can be done in  

many ways,

so the probability is 126/286=0.44

Did this help??

8 0
3 years ago
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