The equation in y=mx+b form is 1/4x-9.
To answer this question, you need to know that a quarter is worth $0.25 and dimes worth $0.10. In this case, the total number of money that made from quarters and dimes is $2.80
With Q=quarter and D=dime, then the equation should be:
2.80= 0.25 Q + 0.10 D
The condition that needs to be fulfilled in this case is that the quarter should be 8 more than dimes. Then you need to find out the highest possible number of the quarter and lowest possible number of the dimes.
If you divide 2.8 with 0.25 you will found it will be 11.2 but 11 quarter will result with 0.05 value which you cannot remove, so the highest possible of the quarter should be 10.
If the highest possible of the quarter is 10, then the lowest possible of dimes should be:
2.8= 0.25(10) + 0.10D
0.10D= 0.3
D=3
Since 10-3 is 7, then it is not possible for the quarter to be 8 more than the dimes.
Answer:
move the decimal in 1.4 two places two the right and do the same with 3.36 then divide
Step-by-step explanation:
Answer: search it and i cant see well so sorry
Step-by-step explanation: research
Answer:
she spent $1782
Step-by-step explanation:
first we have to find out her total money then minus 990
to get that 990 /5 then multipliedby 6 is 1188
1188 over 3 then times by 7 is 2772
2772 is the total amount of money she had. minus what she had left which is 990 she has spent 1782 dollars