1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Cerrena [4.2K]
4 years ago
13

An object moving with a speed v0 collides head-on with a second object initially at rest. A student assumes the collision is ela

stic and calculates the speeds of the two objects and the speed of the center of mass of the objects after the collision. If the student assumes the collision was perfectly inelastic, how would that change the way the student calculated the list values?
A. The student only uses conservation of kinetic energy for inelastic collisions, but used both conservation of kinetic energy and momentum for elastic collisions
B. The student only uses conservation of momentum for inelastic collisions, but used both conservation of kinetic energy and momentum for elastic collisions
C. The student only uses conservation of kinetic energy for the final speeds of the two objects in inelastic collisions, but only uses conservation of momentum for speed of the center of mass
D. The student only uses conservation of momentum for the final speeds of the two objects in inelastic collisions, but only uses conservation of kinetic energy for speed of the center of mass
E. The student only uses conservation of momentum for the final speeds of the two objects in elastic collisions, but only uses conservation of kinetic energy for speed of the center of mass
Physics
1 answer:
AleksAgata [21]4 years ago
6 0

Answer:B

Explanation:

It is given that the first collision is elastic so we can conserve momentum as well as the kinetic energy of the system.

The value of the coefficient of restitution is equal to one for an elastic collision. An elastic collision is also called a perfectly Elastic collision.

A perfectly inelastic collision is one in which there is the loss of kinetic energy and some of the kinetic energy is converted into another form of energy, for example, internal energy.

although momentum is conserved in Inelastic collision kinetic energy is not conserved.    

You might be interested in
A bottle rocket takes off with a = 34.5 m/s2. It
sergiy2304 [10]

Answer:3.4 seconds

Explanation:

Initial velocity(u)=0

acceleration=34.5m/s^2

Height(h)=200m

Time =t

h=u x t - (gxt^2)/2

200=0xt+(34.5xt^2)/2

200=34.5t^2/2

Cross multiply

200x2=34.5t^2

400=34.5t^2

Divide both sides by 34.5

400/34.5=34.5t^2/34.5

11.59=t^2

t^2=11.59

Take them square root of both sides

t=√(11.59)

t=3.4 seconds

8 0
3 years ago
A 10 m long uniform beam weighing 100 N is supported by two ropes at the ends. If a 400 N person sits at 2.0 m from one end of t
Naddik [55]

Answer:

T1 = 130N, T2 = 370N

Explanation:

In order for the system to be at rest, the sum of all forces must be zero and the torque around a point on the beam must be zero.

1. forces:

Let tension in rope 1 be T1 and in rope 2 be T2:

ma = T1 + T2 - 100N - 400N = 0

(1) T1 + T2 = 500N

2. torque around the center point of the beam:

τ = r x F = 5*T1 + 3*400N - 5*T2 = 0

(2) T1 - T2 = -240N

Solving both equations:

T1 = 130N

T2 = 370N

3 0
4 years ago
for the primitive yo-yo in fig, to find the downward acceleration of the cylinder and the tension in the string. you can take th
mixas84 [53]

The downward acceleration of the solid cylinder at the given tension in the string is determined as 2Tr/MR.

<h3>Downward acceleration of the cylinder</h3>

The downward acceleration of the solid cylinder is determined from the principle of conservation of angular momentum as shown below;

Iα = Tr

where;

  • I is moment of inertia of the solid cylinder
  • α is angular acceleration of the cylinder
  • T is tension in the string
  • r is length of the string

α = Tr/I

\frac{a}{R} = \frac{Tr}{I} \\\\\frac{a}{R} = \frac{Tr}{\frac{1}{2} MR^2}\\\\\frac{a}{R} =\frac{2Tr}{MR^2} \\\\a = \frac{2Tr}{MR}

where;

  • a is the downward acceleration of the solid cylinder
  • R is radius of the cylinder

Thus, the downward acceleration of the solid cylinder at the given tension in the string is determined as 2Tr/MR.

Learn more about acceleration here: brainly.com/question/605631

#SPJ1

7 0
2 years ago
Please help!! 20 points!!
Zigmanuir [339]

Answer:

4

Explanation:

5 0
3 years ago
Read 2 more answers
The force of attraction between two objects, which is related to the object's mass is the definition of
Andrews [41]
This would be the definition of gravitational force, I believe. The force of attraction between 2 objects based on the mass of the objects.
7 0
3 years ago
Read 2 more answers
Other questions:
  • A baseball is moving at a speed of 2.2\,\dfrac{\text{m}}{\text{s}}2.2 s m ​ 2, point, 2, space, start fraction, m, divided by, s
    9·1 answer
  • The rope of the length 6 m is fixed to a vertical wall in the horizontal x-direction. We send one transverse pulse on a rope in
    6·1 answer
  • John ( body mass= 65 kg) is taking off for a long jump . Horizontal accerleration ax is 5m/s^2 and vertical acceleration ay is 0
    9·1 answer
  • The equation for momentum is p=mv. Which letter represents the momentum? Question 2 options: p m v
    9·1 answer
  • Which layer of the sun's atmosphere are you looking at when you look at me in image of the Sun
    6·1 answer
  • You do 1200J of work with gears.If the gears do 1000J of work, what is the efficiency of the gears?
    14·1 answer
  • In a tug of war between Mrs. Brenneman and Mr. Schroedl seems at a standstill. Then Mrs. Brenneman tugs hard giving a force of 4
    15·1 answer
  • Explain what is meant by “In Phase” and “Out of Phase?
    9·2 answers
  • An 8 kg toddler is running at a speed of 10 m/s.<br> how much energy does he have?
    14·1 answer
  • if a cyclist traveled southwest a distance of 12,250 meters in 1.7 hrs what would the velocity of the cyclist be?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!