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Juliette [100K]
3 years ago
6

You find a geode while hiking. You place it on a scale and find it has a mass of 62 g.

Chemistry
1 answer:
dexar [7]3 years ago
5 0

Answer:

B

Explanation:

I think that's it.. hope I helped you

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What is the density if<br> a sample of rock has a mass of 69<br> g and a volume of<br> 23<br> ml?
kiruha [24]
Density = mass / volume

= 69g / 23 ml

= 3 g / ml.

Thus, the density of the sample is 3 grams per ml or 3g/ ml
4 0
3 years ago
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How many hydrogen atoms are in 89.5 g of<br> C6H6 ?<br> Answer in units of atoms.
Elodia [21]

Solution :

Molar mass of C_6H_6 is :

M = 6×12 + 6×1 g

M = 78 g

78 gram of C_6H_6 contains 6.022 \times 10^{23} molecules.

So, 89.5 gram of C_6H_6 contains :

n = 6.022 \times 10^{23} \times \dfrac{89.5}{78}\\\\n = 6.91 \times 10^{23}

Now, from the formula we can see that one molecule of C_6H_6 contains 2 hydrogen atom . So, number of hydrogen atom are :

h = 2\times 6.91 \times 10^{23}\\\\h = 1.38 \times 10^{22}\ atoms

Hence, this is the required solution.

8 0
3 years ago
6. Cuando se oxidan en el aire 12,120 g de vapor de Zinc se obtienen 15,084 g del óxido. ¿Cuál es la fórmula empírica del óxido?
Eddi Din [679]

Answer:

 12120 g  +    O2        =    15084 g

m Zn = 12.120 Kg

m óxido = 15.084 Kg

1. calcular la masa de cinc en gramos

g = 12,120 Kg x 1000 = 12120 g de cinc

g = 15.084 Kg x 100 = 15084 g de oxígeno

2.  calcular gramos de Oxigeno

g O = 15084 g - 12120 g = 2964 g O2

3. calcular % de Zn y O

%m/m ( m soluto / m solc.) x 100

%m/m (Zn) =  ( 1210 g / 15084 g ) x 100

% m/m (Zn) = 80.35 % = 80.35 g

%m/m (O) =  ( 2964 g / 15084 g ) x 100

% m/m (Zn) = 19.65 %  = 19.65 g

4. Calcular moles de cada elemento

Zn: 80.35 g / 65.38 g/mol = 1.228 mol

O: 19.65 g / 16 g/mol = 1.228 mol

5. dividir entre el menor de los elementos

Zn: 1.228 mol / 1.228 mol = 1

O: 1.228 mol / 1.228 mol = 1

6. Fórmula empírica: ZnO

3 0
3 years ago
Element A has a half-life of 10 days. A scientist measures out 200 g of this substance. After 30 days has passed, the scientist
myrzilka [38]
N=N₀*2^(-t/T)

N₀=200 g
T=10 d
t=30 d

N=200*2^(-30/10)=25 g

25 g will remain
4 0
3 years ago
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Someone help me with question pls
gizmo_the_mogwai [7]

Explanation:

the conductors are the three u have checked

8 0
2 years ago
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