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a_sh-v [17]
3 years ago
13

What force is necessary to accelerate a 1,200 kg car at a rate of 35 m/s2?

Chemistry
1 answer:
Zarrin [17]3 years ago
6 0

Explanation:

Given that,

Mass of a car, m = 1200 kg

Acceleration of the car, a = 35 m/s²

The force acting on the car is given by :

F = ma

F = 1200 kg × 35 m/s²

= 42000  N

If the force is 30,600 N, then acecleration is given by :

a=\dfrac{F}{m}\\\\a=\dfrac{30600}{1200}\\\\a=25.5\ m/s^2

Hence, this is the required solution.

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Lab 2: paper chromatography of organic dyes<br> Picture of questions below.
Anika [276]

Answer:

The three primary colors used when mixing dyes or paints are red, yellow, and blue. Other colors are often a mixture of these three colors. Try running a chromatography test again with non-primary-color markers, like purple, brown, and orange.

Explanation:

<h3><em>Mixtures that are suitable for separation by chromatography include inks, dyes and colouring agents in food. ... As the solvent soaks up the paper, it carries the mixtures with it. Different components of the mixture will move at different rates. This separates the mixture out.</em></h3>

<em />

7 0
3 years ago
How many atoms of hydrogen are present in 2.92 g of water?
Wittaler [7]
The molecular weight of water is <span>18.01528 g/mol.
So in 2.92 grams there are 2.92/</span>18.01528 = 0.1621 mol of particles.

1 mol contains 6,02214 × 10^<span>23 particles by definition.

So the nr of H2O molecules is </span>0.1621 * 6,02214 × 10^23 = 0,9761 × 10^23.

Every molecule has 2 H atoms, so you have to double that.

2* 0,9761 × 10^23 = 1.952 × 10^23.
3 0
3 years ago
Read 2 more answers
2NO(g) N2(g) + O2(g); Keq = 2.1 × 1030 What does the value of the equilibrium constant indicate?
olga_2 [115]
The equilibrium constant is a value which represents the equilibrium of a reaction. It is a reaction quotient when the reaction reached equilibrium. If Keq is greater than 1, the mixture contains mostly the products. On the other hand, if Keq is less than 1, the mixture contains the reactants. For this case, the mixture contains mostly products.
7 0
3 years ago
The half-life of a first-order reaction is 13 min. If the initial concentration of reactant is 0.085 M, how long would it take u
olasank [31]

Answer: It will take 8.2 minutes until the concentration decreases to 0.055 M

Explanation:

The time after which 99.9% reactions gets completed is 40 minutes

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process  

a) for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

k=\frac{0.693}{13min}=0.053min^{-1}

b)  Time taken for 0.085 M to decrease to 0.055 M

t=\frac{2.303}{0.053}\log\frac{0.085}{0.055}

t=8.2min

Thus it will take 8.2 minutes until the concentration decreases to 0.055 M

5 0
3 years ago
Please help...awarding brainliest if correct and lots of points.
abruzzese [7]

Silver chloride produced : = 46.149 g

Limiting reagent : CuCl2

Excess remains := 3.74 g

<h3>Further explanation</h3>

Reaction

silver nitrate + copper(II) chloride ⇒ silver chloride + copper(II) nitrate

Required

silver chloride produced

limiting reagent

excess remains

Solution

Balanced equation

2AgNO3 (aq) + CuCl2 (s) → 2AgCl(s) + Cu(NO3)2(aq)

mol AgNO3 :

= 58.5 : 169,87 g/mol

= 0.344

mol CuCl2 :

=21.7 : 134,45 g/mol

= 0.161

mol ratio : coefficient of AgNO3 : CuCl2 :

= 0.344/2 : 0.161/1

= 0.172 : 0.161

CuCl2  as a limiting reagent

mol AgCl :

= 2/1 x 0.161

= 0.322

Mass AgCl :

= 0.322 x 143,32 g/mol

= 46.149 g

mol remains(unreacted) for AgNO3 :

= 0.344-(2/1 x 0.161)

= 0.022

mass AgNO3 remains :

= 0.022 x 169,87 g/mol

= 3.74 g

8 0
3 years ago
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