I would love to help but it is 3 or is it 3 million?
You may find bellow the balanced chemical equations.
Explanation:
Molecular equations:
3 Sr(NO₃)₂ (aq) + 2 K₃PO₄ (aq) → Sr₃(PO₄)₂ (s) + 6 KNO₃ (aq)
2 NaOH (aq) + Ni(NO₃)₂ (aq) = Ni(OH)₂ (s) + 2 NaNO₃ (aq)
Ionic equations:
3 Sr²⁺ (aq) + 6 NO₃⁻ (aq) + 6 K⁺ (aq) + 2 PO₄³⁻ (aq) → Sr₃(PO₄)₂ (s) + 6 K⁺ (aq) + 6 NO₃⁻ (aq)
2 Na⁺ (aq) + 2 OH⁻ (aq) + Ni²⁺ (aq) + 2 NO₃⁻ (aq) = Ni(OH)₂ (s) + 2 Na⁺ (aq) + 2 NO₃⁻ (aq)
To get the net ionic equation we remove the spectator ions:
3 Sr²⁺ (aq) + 2 PO₄³⁻ (aq) → Sr₃(PO₄)₂ (s)
2 OH⁻ (aq) + Ni²⁺ (aq) = Ni(OH)₂ (s)
Learn more about:
net ionic equations
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Answer:
7.90×10²¹ formula units
Explanation:
From the question given above, the following data were obtained:
Mass of Cu(NO₃)₂ = 2.46 g
Formula units of Cu(NO₃)₂ =?
From Avogadro's hypothesis,
1 mole of Cu(NO₃)₂ = 6.02×10²³ formula units
Next, we shall determine the mass of 1 mole of Cu(NO₃)₂. This can be obtained as follow:
1 mole of Cu(NO₃)₂ = 63.5 + 2[14 + (3×16)]
= 63.5 + 2[14 + 48]
= 63.5 + 2[62]
= 63.5 + 124
= 187.5 g
Thus,
187.5 g of Cu(NO₃)₂ = 6.02×10²³ formula units
Finally, we shall determine the formula units contained in 2.46 g of Cu(NO₃)₂. This can be obtained as follow:
187.5 g of Cu(NO₃)₂ = 6.02×10²³ formula units.
Therefore,
2.46 g of Cu(NO₃)₂ =
(2.46 × 6.02×10²³)/187.5
= 7.90×10²¹ formula units
Thus, 2.46 g of Cu(NO₃)₂ contains 7.90×10²¹ formula units
Answer:
The valence electrons are the only parts of an atom that make chemical bonds. Noble gases don't form chemical bonds because they have a full outer shell (8 electrons).
