In a study of the conversion of methane to other fuels, a chemical engineer mixes gaseous methane and gaseous water in a 0.778 L
1 answer:
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The solution for problem 36 is in the picture attached. I am 80% sure it’s correct.
The energy absorbed by the system before the reaction start has been 752 kJ/mol.
The bond energy has been defined as the energy possessed by the bond that has been converted into the heat energy and utilized in the reaction.
The energy has been conserved in a chemical reaction. Thus, the energy absorbed by the reactant in the reaction has been the difference in the energy of the reactant and product.
<h3>Computation for the energy absorbed</h3><h3 />The given reaction has been:
The bond energy of the reactant has been:
H-H bond energy = 432 kJ/mol
2 C=O bond energy= 799 kJ/mol
The total energy of the reactant has been 432 kJ/mol + 799 kJ/mol
The total energy of the reactant has been 1231 kJ/mol
The bond energy of the product has been:
C-O bonds = 358 kJ/mol
C=O bonds = 745 kJ/mol
1 C-H bond = 413 kJ/mol
1 O-H bond = 467 kJ/mol
The total energy of the product has been 358 + 745 + 413 + 467 kJ/mol
The total energy of the product has been 1,983 kJ/mol
According to the law of conservation of energy:
Substituting the values for energy absorbed:
The energy absorbed by the system before the reaction start has been 752 kJ/mol.
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Answer:
, zirconium-103.
Explanation:
In a nuclear reaction, both the mass number and atomic number will conserve.
Let represent the unknown particle.
The mass number of a particle is the number on the upper-left corner. The atomic number of a particle is the number on its lower-left corner under the mass number. For example, for the particle ,
is the mass number while
while
is the atomic number.
Sum of mass numbers on the left-hand side of the equation:
.
Note that there are three neutrons on the right-hand side of the equation. Sum of mass numbers on the right-hand side:
.
Mass number conserves. As a result,
.
Solve this equation for :
.
Among the five choices, the only particle with a mass number of 103 is . Make sure that atomic number also conserves.
91.4 grams
91.4 grams of kcl in grams must be added to 500 ml of a 0. 15 m kcl solution to produce a 0. 40 m solution.
C = mol/volume
2.45M=mol/0.5L
2.45M⋅0.5L = mol
mol = 1.225
Convert no. of moles to grams using the atomic mass of K + Cl
1.225mol *
mol=1.225
=1.225 mol .
=1.225 . 74.6
=91.4g
therefore, 91.4 grams of kcl in grams must be added to 500 ml of a 0. 15 m kcl solution to produce a 0. 40 m solution.
What is 1 molar solution?
In order to create a 1 molar (M) solution, 1.0 Gram Molecular Weight of the chemical must be dissolved in 1 liter of water.
58.44 g make up a 1M solution of NaCl.
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