Draw all constitutional isomers with molecular formula c3h8o, and rank them in terms of increasing acidity:
1 answer:
There are only <em>three</em> constitutional isomers (see the image below).
Ethyl methyl ether is the least acidic because it has only C-H bonds. However, it should be more acidic than an alkane (pKₐ ≈ 50) because of the electron withdrawing effect of the O atom. I would expect it to have pKₐ ≈ 30.
The alcohols are <em>more acidic</em> because the O in the O- H bond is highly electron withdrawing. Alcohols typically have pKₐ ≈ 17.
Alkyl groups are electron-donating. This increases electron density in the OH bond and makes the acid weaker. Propan-2-ol has two methyl groups on the α-carbon, while propan-1-ol has one ethyl group. Thus propan-2-ol should be a <em>slightly weaker</em> acid than propan-1-ol.
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Answer: 14.62 ml
Explanation:
Molarity is defined as the number of moles of solute dissolved per liter of the solution.
where,
n= moles of solute
= volume of solution in ml = 250 ml
Now put all the given values in the formula of molarity, we get
To calculate the volume of base, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
Thus the volume of NaOH solution the student will need to add to reach the final equivalence point is 14.62 ml