What is the change in enthalpy when 180 g of water vapor condenses at 100°C? (AH, = 40.67 kJ/mol)
1 answer:
Answer:
Explanation:
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In this case, considering that the heat has two forms, sensible (variable temperature) and latent (constant temperature), we can notice that phase changes account for latent heat as the temperature remains the same. In such a way, given the enthalpy of vaporization of water, 40.67 kJ/mol, the enthalpy of condensation (reverse process) is the negative value, -40.67 kJ/mol; therefore, the associated latent heat would be:
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Answer:
D) 1.61 times faster
Explanation:
= √(3)RTM
R constant= 0.08206
T=constant, so in this problem we dont need a value for it
M=17.031 g/mol
√(3)(0.08206)(17.031)= 2.047
= √(3)RTM
R constant= 0.08206
T=constant, so in this problem we dont need a value for it
M= 44.01 g/mol
√(3)(0.08206)(44.01)= 3.29
Since we are trying to measure how much faster NH3 will be, we have to realize that mass and speed have an inverse relationship.
So instead of doing (2.047)/(3.29) = 6.22
we have to flip the values to get (3.29)/(2.047)= 1.61