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statuscvo [17]
3 years ago
8

A silver nitrate, AgNO3, solution of unknown concentration was discovered in the lab. To determine the concentration of the solu

tion, a concentration cell was set up with the unknown solution in the anode compartment and a 1.0 M AgNO3 solution in the cathode compartment. The cell had a potential (E) of +0.045 V at 25°C. What is the concentration of silver in the unknown solution?
Chemistry
1 answer:
harina [27]3 years ago
3 0

Answer:

0.174 M

Explanation:

The same can be solve by using Nernst's equation

The Nernst's equation is:

Ecell=E^{0}_{cell}-\frac{0.0592}{n}log\frac{[anodic]}{[cathodic]}

For silver cell

n= 1

As both the compartments have silver nitrate solution,t the standard emf of cell will be zero.

Given

Ecell = 0.045

[Anodic compartment]= 1 M

Putting values

0.045 = 0 -\frac{0.0592}{1}log(\frac{1}{x} )

0.760=log(\frac{1}{x})

Taking antilog and solving

[AgNO3]=0.174 M

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What mass (g) of magnesium nitride (Mg3N2) can be made from the reaction of 1.22 g of magnesium with excess nitrogen? __Mg + __N
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<h3>Answer:</h3>

1.69 g Mg₃N₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
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[RxN - Balanced] 3Mg + N₂ → Mg₃N₂

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<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.68873 g Mg₃N₂ ≈ 1.69 g Mg₃N₂

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