Answer:
c. fluorine
Explanation:
A single replacement reaction is defined as the chemical reaction in which a strong molecule replaces the weak molecule from a compound.
In a single replacement reaction, the chloride ion in NaCl can be replaced by fluorine and gives Sodium fluoride as fluorine (F) is stronger than chlorine (Cl) and from other given molecules also. So the single replacement reaction between NaCl and F will be:
NaCl + F2 => NaF + Cl2
Hence, the correct answer is "c. fluorine".
Answer:
The equilibrium constant for CO now
= 0.212 M
For H₂O
= 0.212 M
For CO₂ = x = 0.2880 M
For H₂ = x = 0.2880 M
Explanation:
The chemical equation for the reaction is:
CO(g) + H2O(g) ⇌ CO2(g) + H2(g)
The ICE Table for this reaction can be represented as follows:
CO(g) + H2O(g) ⇌ CO2(g) + H2(g)
Initial 0.5 0.5 - -
Change -x -x + x + x
Equilibrium 0.5 -x 0.5 - x
The equilibrium constant![K_c = \dfrac{[x][x]}{[0.5-x][0.5-x]}](https://tex.z-dn.net/?f=K_c%20%3D%20%5Cdfrac%7B%5Bx%5D%5Bx%5D%7D%7B%5B0.5-x%5D%5B0.5-x%5D%7D)
![K_c = \dfrac{[x]^2}{[0.5-x]^2}](https://tex.z-dn.net/?f=K_c%20%3D%20%5Cdfrac%7B%5Bx%5D%5E2%7D%7B%5B0.5-x%5D%5E2%7D)
where; 



1.3583 (0.5-x) = x
0.67915 - 1.3583x = x
0.67915 = x + 1.3583x
0.67915 = 2.3583x
x = 0.67915/2.3583
x = 0.2880
The equilibrium constant for CO now = 0.5 - x
= 0.5 - 0.2880
= 0.212 M
For H₂O = 0.5 - x
= 0.5 - 0.2880
= 0.212 M
For CO₂ = x = 0.2880 M
For H₂ = x = 0.2880 M
Answer:
I think it's C but I'm atlessy 60% sure :]
<u>Answer:</u> The boiling point of water in Tibet is 69.9°C
<u>Explanation:</u>
To calculate the boiling point of water in Tibet, we use the Clausius-Clayperon equation, which is:
![\ln(\frac{P_2}{P_1})=\frac{\Delta H}{R}[\frac{1}{T_1}-\frac{1}{T_2}]](https://tex.z-dn.net/?f=%5Cln%28%5Cfrac%7BP_2%7D%7BP_1%7D%29%3D%5Cfrac%7B%5CDelta%20H%7D%7BR%7D%5B%5Cfrac%7B1%7D%7BT_1%7D-%5Cfrac%7B1%7D%7BT_2%7D%5D)
where,
= initial pressure which is the pressure at normal boiling point = 1 atm = 760 mmHg (Conversion factor: 1 atm = 760 mmHg)
= final pressure = 240. mmHg
= Heat of vaporization = 40.7 kJ/mol = 40700 J/mol (Conversion factor: 1 kJ = 1000 J)
R = Gas constant = 8.314 J/mol K
= initial temperature or normal boiling point of water = ![100^oC=[100+273]K=373K](https://tex.z-dn.net/?f=100%5EoC%3D%5B100%2B273%5DK%3D373K)
= final temperature = ?
Putting values in above equation, we get:
![\ln(\frac{240}{760})=\frac{40700J/mol}{8.314J/mol.K}[\frac{1}{373}-\frac{1}{T_2}]\\\\-1.153=4895.36[\frac{T_2-373}{373T_2}]\\\\T_2=342.9K](https://tex.z-dn.net/?f=%5Cln%28%5Cfrac%7B240%7D%7B760%7D%29%3D%5Cfrac%7B40700J%2Fmol%7D%7B8.314J%2Fmol.K%7D%5B%5Cfrac%7B1%7D%7B373%7D-%5Cfrac%7B1%7D%7BT_2%7D%5D%5C%5C%5C%5C-1.153%3D4895.36%5B%5Cfrac%7BT_2-373%7D%7B373T_2%7D%5D%5C%5C%5C%5CT_2%3D342.9K)
Converting the temperature from kelvins to degree Celsius, by using the conversion factor:


Hence, the boiling point of water in Tibet is 69.9°C
Answer: the correct answer would be the last option, C6H12O6 and O2
Explanation: