All categories

3 years ago

Would an opah fish be better suited to live in cold water or warm water? explain why

Chemistry

1 answer:

Kaylis [27]3 years ago

4 0

Don't blame me if you get it wrong i'm a dumb but yet successful student

Warm blood gives deep-sea fish a boost, according to Wegner. The opah's muscles and nervous system likely function faster than an equivalent fish with cold blood. ... This fish, the southern opah, lives in colder waters than the northern opah, so it would be harder to keep warm, Wegner said — but even more beneficial.

You might be interested in

Discuss FOUR ways in which one's acceptance of responsibility can influence

andrew11 [14]

Answer:

being responsible is owing up to the possible

consequences of your decision whether it was right or wrong.

communication is a two way process in which there is a messenger and receiver

one of the ways by which a person could be responsible is by saying 'I'

in all the things he would say, instead of 'we'

for example , " We don't like the way you acted a while ago " , change it to i don't like tye way you acted a while ago.

here u r establishing ownership on the things you want to say to the person

8 0

3 years ago

alcohol and other drugs can stimulate, inhibit or halt release of chemicals that help the brain function. true or false

snow_lady [41]

Cmon man... true!
SAY NO TO DRUGS. and alcohol

4 0

3 years ago

Read 2 more answers

Describe the four types of fronts and the weather associated with each.

FrozenT [24]

The Four type is

Cold front

Warm front

Stationary front

Occluded front

3 0

3 years ago

Which electrophiles can react with an enol?

dlinn [17]

THE MOLECULE HAS A C=C AND AN -OH GROUP, SO IT IS CALLED AN ENE/OL, I.E., AN ENOL. ENOLS CAN BE FORMED ONLY FROM CARBONYL COMPOUNDS WHICH HAVE ALPHA HYDROGENS. THEY CAN BE FORMED BY ACID OR BASE CATALYSIS, AND ONCE FORMED ARE HIGHLY REACTIVE TOWARD ELECTROPHILES, LIKE BROMINE.

8 0

3 years ago

A gaseous mixture composed of 20% CH4, 30% C2H4, 35% C2H2, and 15% C2H20. What is the average molecular weight of the mixture? a

Semenov [28]

<u>Answer:</u> The correct answer is Option d.

<u>Explanation:</u>

We are given:

Mass percentage of $CH_4$ = 20 %

So, mole fraction of $CH_4$ = 0.2

Mass percentage of $C_2H_4$ = 30 %

So, mole fraction of $C_2H_4$ = 0.3

Mass percentage of $C_2H_2$ = 35 %

So, mole fraction of $C_2H_2$ = 0.35

Mass percentage of $C_2H_2O$ = 15 %

So, mole fraction of $C_2H_2O$ = 0.15

We know that:

Molar mass of $CH_4$ = 16 g/mol

Molar mass of $C_2H_4$ = 28 g/mol

Molar mass of $C_2H_2$ = 26 g/mol

Molar mass of $C_2H_2O$ = 48 g/mol

To calculate the average molecular mass of the mixture, we use the equation:

$\text{Average molecular weight of mixture}=\frac{_{i=1}^n\sum{\chi_im_i}}{n_i}$

where,

$\chi_i$ = mole fractions of i-th species

$m_i$ = molar masses of i-th species

$n_i$ = number of observations

Putting values in above equation:

$\text{Average molecular weight}=\frac{(\chi_{CH_4}\times M_{CH_4})+(\chi_{C_2H_4}\times M_{C_2H_4})+(\chi_{C_2H_2}\times M_{C_2H_2})+(\chi_{C_2H_2O}\times M_{C_2H_2O})}{4}$

$\text{Average molecular weight of mixture}=\frac{(0.20\times 16)+(0.30\times 28)+(0.35\times 26)+(0.15\times 42)}{4}\\\\\text{Average molecular weight of mixture}=6.75$

Hence, the correct answer is Option d.

3 0

3 years ago