We can use the ideal gas law equation to find the volume occupied by oxygen gas
PV = nRT
where ;
P - pressure - 52.7 kPa
V - volume
n - number of oxygen moles - 12.0 g / 32 g/mol = 0.375 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 25 °C + 273 = 298 K
substituting the values in the equation
52 700 Pa x V = 0.375 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K
V = 17.6 L
volume of the gas is 17.6 L
Answer:
option A
an increase in entropy and a decrease in enthalpy
pls mark brainliest
Answer:
There are 0,2 moles of gas that ocuppy the container.
Explanation:
We apply the formula of the ideal gases, we clear n (number of moles); we use the ideal gas constant R = 0.082 l atm / K mol. Firs we convert the unit of temperature in Celsius into Kelvin:
0°C= 273 K ------> 45,6 °C= 273 + 45, 6= 318, 6 K
PV= nRT ---> n= PV/RT
n= 1,48 atm x 3,45 L /0.082 l atm / K mol x 318,6 K
n= 0,195443479 mol
Answer:
im not a brain wiz but i think 20
Explanation:
