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Viefleur [7K]
3 years ago
9

When DNA is replicated, it is necessary for the two strands to "unzip" temporarily. Choose which bonding type is most appropriat

e for holding the strands together in this way.
A) ionic bonding
B) hydrogen bonding
C) non-polar covalent bonding D) polar covalent bonding
Chemistry
1 answer:
wariber [46]3 years ago
5 0

Answer: B) hydrogen bonding

Explanation:

A) An ionic bond is formed when an element completely transfers its valence electron to another element.

B) Hydrogen bonds are special type of dipole dipole forces which are formed when hydrogen bonds with an electronegative element.

DNA strands are held together by hydrogen bonds between the bases on one strand and those on the other. Adenine and thymine have two hydrogen bonds between them while cytosine and guanine have three hydrogen bonds between them.

C) Non-polar covalent bond is defined as the bond which is formed when there is no difference of electronegativities between the atoms.

D) A polar covalent bond is defined as the bond which is formed when there is a difference of electronegativities between the atoms.

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r-ruslan [8.4K]

The molar concentration will be greater than 0.01 M KIO_{3}.


Since more of the compound was measured out than what was calculated, you can think of the solution as being 'stronger' than what it was calculated to be. Since a 'stronger' concentration results in a number that is higher, the molarity of this solution is going to be greater than 0.01 M.

7 0
2 years ago
Chemistry. Will mark Brainly.
kogti [31]

Answer:

c is right

Explanation:

8 0
2 years ago
Using Argn (n= –2, –1, 0, +1, +2, etc.) to represent the different charge species of Arginine, what is the dominant species of A
fredd [130]

Answer:

Explanation:

From the sorensen equation; pH = -Log[H+]

2.7 = -Log[H+]

H+ = 10^-2.7

H+ = 0.001995M = Hydrogen ion concentration

Basically, the more the charges, the higher the hydrogen ion concentration stand vice versa. +2 has the highest concentration.

6 0
2 years ago
Calculate the standard reaction Gibbs free energy for the following cell reactions: (a) 2 Ce41(aq) 1 3 I2(aq) S 2 Ce31(aq) 1 I32
Law Incorporation [45]

<u>Answer:</u>

<u>For a:</u> The standard Gibbs free energy of the reaction is -347.4 kJ

<u>For b:</u> The standard Gibbs free energy of the reaction is 746.91 kJ

<u>Explanation:</u>

Relationship between standard Gibbs free energy and standard electrode potential follows:

\Delta G^o=-nFE^o_{cell}           ............(1)

  • <u>For a:</u>

The given chemical equation follows:

2Ce^{4+}(aq.)+3I^{-}(aq.)\rightarrow 2Ce^{3+}(aq.)+I_3^-(aq.)

<u>Oxidation half reaction:</u>   Ce^{4+}(aq.)\rightarrow Ce^{3+}(aq.)+e^-       ( × 2)

<u>Reduction half reaction:</u>   3I^_(aq.)+2e^-\rightarrow I_3^-(aq.)

We are given:

n=2\\E^o_{cell}=+1.08V\\F=96500

Putting values in equation 1, we get:

\Delta G^o=-2\times 96500\times (+1.80)=-347,400J=-347.4kJ

Hence, the standard Gibbs free energy of the reaction is -347.4 kJ

  • <u>For b:</u>

The given chemical equation follows:

6Fe^{3+}(aq.)+2Cr^{3+}+7H_2O(l)(aq.)\rightarrow 6Fe^{2+}(aq.)+Cr_2O_7^{2-}(aq.)+14H^+(aq.)

<u>Oxidation half reaction:</u>   Fe^{3+}(aq.)\rightarrow Fe^{2+}(aq.)+e^-       ( × 6)

<u>Reduction half reaction:</u>   2Cr^{2+}(aq.)+7H_2O(l)+6e^-\rightarrow Cr_2O_7^{2-}(aq.)+14H^+(aq.)

We are given:

n=6\\E^o_{cell}=-1.29V\\F=96500

Putting values in equation 1, we get:

\Delta G^o=-6\times 96500\times (-1.29)=746,910J=746.91kJ

Hence, the standard Gibbs free energy of the reaction is 746.91 kJ

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3 years ago
Hat kind of connection is Molly likely to make with Jane?
Aneli [31]

Answer:

ur question doesnt make sense :)

Explanation:

8 0
2 years ago
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