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2 years ago

If frequency is kept constant, how are the velocity and wavelength of a wave related?

2 answers:

4 0

Wave speed = (frequency) x (wavelength)

If the frequency is kept constant, then the wavelength
is directly proportional to the wave speed.

Elan Coil [88]2 years ago

3 0

<h3>Answer;</h3>

Velocity and wavelength are directly proportional when frequency is kept constant.

<h3>Explanation;</h3>

Frequency of a wave is the number of complete oscillations made by a given wave in one second.
Wavelength on the other hand, is the distance between two successful crests or troughs in a transverse wave or two successful rarefactions or compressions in a longitudinal waves.
The speed of a wave is given by the product of the frequency of a wave and the wavelength.
Speed = Frequency × wavelength, 
Therefore, if frequency is kept constant, then the speed of a wave is directly proportional to the wavelength, such that an increase in wavelength increases the speed of the wave and vice versa.

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2 years ago

Read 2 more answers

A reactor operating at 1 MW is scrammed by instantaneous insertion of $5.00 of negative reactivity. Approximately how long does

Novosadov [1.4K]

Answer:

time is 3333.33 min or 55.55 hr

Explanation:

given data

reactor operating = 1 MW

negative reactivity = $5

power = 1 miliwatt

to find out

how long does it take

solution

we know here power coefficient that is

power coefficient = $\frac{10^{6} }{10^{6} }$

power coefficient = 1

so time required to reach power is

power = reactivity × time / power coefficient + reactor operating

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t = 199999.99 sec

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3 years ago

James and John dive from an overhang into the lake below. James simply drops straight down from the edge. John takes a running s

liraira [26]

Answer:

Both of them reach the lake at the same time.

Explanation:

We have equation of motion s = ut + 0.5at²

Vertical motion of James : -

Initial velocity, u = 0 m/s

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Displacement, s = h

Substituting,

s = ut + 0.5 at²

h = 0 x t + 0.5 x g x t²

$t_{James}=\sqrt{\frac{2h}{g}}$

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Initial velocity, u = 0 m/s

Acceleration, a = g

Displacement, s = h

Substituting,

s = ut + 0.5 at²

h = 0 x t + 0.5 x g x t²

$t_{John}=\sqrt{\frac{2h}{g}}$

So both times are same.

Both of them reach the lake at the same time.

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Answer:

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Answer:

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