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Goryan [66]
3 years ago
10

Shakina and Juliette set the car's initial velocity to zero and set the acceleration to +1.2 m/s2, then clicked "start." Answer

the following questions.
What is the car's displacement between 0 and 10.0 s?
What was the total distance traveled by the car during this time interval?
Physics
1 answer:
Tcecarenko [31]3 years ago
4 0
Given:
u = 0, initial velocity
a = 1.2 m/s², acceleration
t = 10.0 , time of travel.

The distance traveled is
s = ut + (1/2)at²
   = (1/2)*(1.2 m/s²)*(10 s)²
   = 60 m

Answer:  60 m

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A rock of mass 0.340 kg is spun horizontally at the end of a wire that has a diameter of 1.00 mm. If the wire gets stretched by
borishaifa [10]

Answer:

Y = 78.13 x 10⁹ Pa = 78.13 GPa

Explanation:

First we will find the centripetal force acting on the wire as follows:

F = mv²/r

where,

F = Force = ?

m = mass of rock = 0.34 kg

v = speed = 19 m/s

r = length of wire

Therefore,

F = (0.34)(19)²/r

F = 122.74/r  

now, we find cross-sectional area of wire:

A = πd²/4

where,

A = Area = ?

d = diameter of wire = 1 mm = 0.001 m

Therefore,

A = π(0.001)²/4

A = 7.85 x 10⁻⁷ m²

Now, we calculate the stress on wire:

Stress = F/A

Stress = (122.74/r)/(7.85 x 10⁻⁷)

Stress = 1.56 x 10⁸/r

Now, we calculate strain:

Strain = Δr/r

where,

Δr = stretch in length = 2 mm = 0.002 m

Therefore,

Strain = 0.002/r

now, for Young's modulus (Y):

Y = Stress/Strain

Y = (1.56 x 10⁸/r)/(0.002/r)

<u>Y = 78.13 x 10⁹ Pa = 78.13 GPa</u>

8 0
3 years ago
Can peer pressure be a cause of conflict?
Studentka2010 [4]

Answer:

yes

Explanation:

it can end up stressing you out, causing a fight or argument

3 0
3 years ago
An object start from rest with a constant acceleration of 8.00 m/s^2 along straight line.
san4es73 [151]
I’ll say c Bc it make more since to find the travel distance
7 0
3 years ago
A meter stick is found to balance at the 49.7-cm mark when placed on a fulcrum. When a 41.5-gram mass is attached at the 28.5-cm
zzz [600]

Answer:

The value is  M  =  42.3 \  kg

Explanation:

From the question we are told that

    The first  position of the fulcrum  is  x = 49.7 cm

    The mass  attached is m  =  41.5 \  g

    The position of the attachment is  x_1 =  28.5 \  cm  

    The second position of the fulcrum is  x_2 = 39.2 \  cm

Generally the sum of clockwise torque =  sum of anti - clockwise torque

So  

       CWT  =  m (x_2 - x_1)

Here CWT  stands for clockwise torque

       ACWT  =  M  ( x - x_2)

So

      m (x_2 - x_1) =    M  ( x - x_2)

=>   41.5  (39.2 -  28.5 ) =    M  ( 49.7  -39.2 )

=>    M  =  42.3 \  kg

3 0
3 years ago
Consider a 7 m stretched string that is clamped at both ends. What is the longest wavelength standing wave that it can support (
user100 [1]

A vibrating stretched string has nodes or fixed points at each end. The string will vibrate in its fundamental frequency with just one anti node in the middle - this gives half a wave.

l=\frac{\lambda }{2}

Rearranging for the wavelength

\lambda=2l

\lambda =2(7)

\lambda = 14m

Therefore the longest wavelength standing wave that it can support is 14m

7 0
4 years ago
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