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TEA [102]
4 years ago
13

A positively charged object will attract an object that has

Physics
1 answer:
ser-zykov [4K]4 years ago
5 0
I’d say a negative charge cause opposites attract but I’m not sure
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A baseball player slides into third base with an initial speed of 4.0 m/s . if the coefficient of kinetic friction between the p
satela [25.4K]
The work done by the friction force to stop the player is equal to his loss of kinetic energy:
W= \Delta K

The work done by the friction force is the magnitude of the force \mu m g times the distance covered by the player, d:
W= \mu mg d

The loss in kinetic energy is simply equal to the initial kinetic energy of the player, since the final kinetic energy is zero (the player comes to rest):
\Delta K=K_i =  \frac{1}{2}mv^2

Substituting into the first equation, we get:
\mu m g d=  \frac{1}{2}mv^2
from which we find d, the distance covered by the player:
d= \frac{v^2}{2 \mu g}= \frac{(4.0 m/s)^2}{2 \cdot 0.4 \cdot 9.81 m/s^2}=2.04 m
4 0
3 years ago
What are the key differences between stored and conservation of energy?
Irina18 [472]
Stored energy=energy that is stored and may not be used, conservation of energy= saved energy that you can use for other things.
7 0
3 years ago
An initially motionless test car is accelerated uniformly to 115 km/h in 8.83 seconds before striking a simulated deer. The car
goblinko [34]

We know the equation of motion v = u+ at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

In this case Final velocity before collision = 115 km/hr = 115*5/18 = 31.94 m/s

Time taken by car to reach this velocity = 8.83 seconds

Initial velocity = 0 m/s

v = u +at

31.94 = 0 + a*8.83

a = 3.62 m/s^2

So acceleration of car just before collision = 3.62 m/s^2

3 0
4 years ago
1.
8_murik_8 [283]

Answer: 2.61 s

Explanation:

We are given the following data:

s=5 ft is the initial height of the object

v=40 ft/s is the initial height of the object

In addition, the motion of the object is given by:

h=-16t^{2}+ vt +s (1)

Where:

h=0 ft is the final height of the object

t is the time the object is in the air before hitting the ground

Rewritting (1) with the given data:

0=-16t^{2}+ 40t +5 (2)

Solving the quadratic equation with the quadratic formula t=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}, where a=-16, b=40, c=5 and choosing the positive value of time:

t=\frac{-40\pm\sqrt{(-40)^{2}-4(-16)(5)}}{2(-16)} (3)

t=2.61 s (4) This is the time

5 0
4 years ago
A heater with an effective resistance of 4.8 ohms is connected to 240.0 volts if it operated approximately 25% of the time and e
agasfer [191]

-- Power used when the heater is running =

                         V²/R = (240)²/4.8= 12,000 watts. (<u>12 KW</u>)

(A gigantic heater ... suitable for maybe a theater, not for a home.)

-- Energy consumed in one day:

                 (12 KW) x (24 hours) x (25%) = <u>72 KwH per day</u>

-- Energy consumed in 30 days:  (72 KwH/day) x (30 days) =

                  <u>2,160 KwH in 30 days</u>

-- Cost = ($0.1 / KwH) x (2,160 KwH) = <em>$216.00</em>  in 30 days


6 0
3 years ago
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