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3 years ago

13

A person pushes a 125 kg object initially at rest on a frictionless surface. The object ends up with a final velocity of 1.40 m/

s. What is the total
translational kinetic energy of the object?

1 answer:

mr Goodwill [35]3 years ago

8 0

Answer:

a person pushes a 125 kg

Explanation:

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What is the characteristic that allows an object to have kinetic energy?

Shtirlitz [24]

Kinetic energy is movement, thus movement would be a characteristic that allows an object to have kinetic energy

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3 years ago

what was the temperature change in Celsius degree if it is changed from 44 degree fahrenheit to -56 degree fahrenheit

wel

Answer:

-11.11 degree Celsius

Explanation:

The change was 44 degree fanhereit

To 56 degree fanhereit

Therefore the temperature range can be calculated as follows

56-44

= 12 degree fanhereit to Celsius

= 12-32×5/9

= -20×5/9

= 100/9

= -11.11 degree Celsius

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3 years ago

Abdou was explaining to a classmate that graphite is a good lubricant

balu736 [363]

The fact that the layers of graphite are held together by only weak Van der Walls forces implies that they can slide over each other.

<h3>Why is graphite a solid lubricant?</h3>

We know that graphite is composed of layers. These hexagonal layers are held together by weak Van Der Walls forces and as such are able to slide over each other. The carbon atom in each layer are held together by strong covalent bonds.

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Thus, the image that shows these layers of graphite is attached to this an answer

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2 years ago

An ac series circuit has an impedance of 60 Ohm and

Iteru [2.4K]

Answer:

Power factor of the AC series circuit is $cos\phi=0.5$

Explanation:

It is given that,

Impedance of the AC series circuit, Z = 60 ohms

Resistance of the AC series circuit, R = 30 ohms

We need to find the power factor of the circuit. It is given by :

$cos\phi=\dfrac{R}{Z}$

$cos\phi=\dfrac{30}{60}$

$cos\phi=\dfrac{1}{2}$

$cos\phi=0.5$

So, the power factor of the ac series circuit is $cos\phi=0.5$ . Hence, this is the required solution.

6 0

3 years ago

An MRI scanner is based on a solenoid magnet that produces a large magnetic field. The magnetic field doesn't stop at the soleno

GaryK [48]

Answer:

The maximum change in flux is $\Delta \o = 0.1404 \ Wb$

The average induced emf $\epsilon =0.11232 V$

Explanation:

From the question we are told that

The speed of the technician is $v = 0.80 m/s$

The distance from the scanner is $d = 1.0m$

The initial magnetic field is $B_i = 0T$

The final magnetic field is $B_f = 6.0T$

The diameter of the loop is $D = 19cm = \frac{19}{100} = 0.19 m$

The area of the loop is mathematically represented as

$A = \pi [\frac{D}{2} ]^2$

$= 3.142 \frac{0.19}{2}$

$= 0.02834 m^2$

At maximum the change in magnetic field is mathematically represented as

$\Delta \o = (B_f - B_i)A$

=> $\Delta \o = (6 -0)(0.02834)$

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The average induced emf is mathematically represented as

$\epsilon = \Delta \o v$

$= 0.1404 * 0.80$

$\epsilon =0.11232 V$

7 0

3 years ago