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Ivan
3 years ago
8

A chemist prepares a solution of copper(l) sulfate (CuSo4) by measuring out 11.7 g of copper(II) sulfate into a 350. mL volumetr

ic flask and filling the flask to the mark with water.
Calculate the concentration in mol/L of the chemist's copper(II) sulfate solution. Be sure your answer has the correct number of significant digits molL x 1
Chemistry
1 answer:
Ksju [112]3 years ago
6 0

Answer:

0.209 mol/L

Explanation:

Given data

  • Mass of copper(lI) sulfate (solute): 11.7 g
  • Volume of solution: 350 mL = 0.350 L

The molar mass of copper(Il) sulfate is 159.61 g/mol. The moles corresponding to 11.7 grams are:

11.7 g × (1 mol/159.61 g) = 0.0733 mol

The molarity of copper(Il) sulfate is:

M = moles of solute / liters of solution

M = 0.0733 mol / 0.350 L

M = 0.209 mol/L

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If you start with 0.30 m mn2 , at what ph will the free mn2 concentration be equal to 4.6 x 10-11 m?
aksik [14]

If you start with 0.30 m Mn₂ , at 12.5 pH, free Mn₂ concentration be equal to 4.6 x 10⁻¹¹ m

Initial molarity of Mn₂ = 0.30 M

Final molarity of Mn₂ = 4.6 x 10⁻¹¹

pH = ?

Ksp [Mn(OH)₂] = 4.6 x 10⁻¹⁴ (standard value)

Write the ionic equation

    Mn(OH)₂   →    Mn⁺² + 2OH⁻

    [Mn⁺²] = 4.6 x 10⁻¹¹

We will calculate the concentration of OH⁻ by using Ksp expression

    Ksp = [Mn⁺²][OH-]²

    [Mn⁺²][OH⁻]² = 4.6 x 10⁻¹⁴

    [OH⁻]² = 4.6 x 10⁻¹⁴ / 4.6 x 10⁻¹¹

    [OH⁻]² = 10⁻³

    [OH⁻] = (10⁻³)¹⁽²

    [OH⁻] = 0.0316 M

Calculate the pOH

    pOH = -log [OH⁻]

    pOH =  -log [0.0316]

    pOH = 1.5

Now calculate pH

   pH = 14 - pOH

   pH = 14 - 1.5

   pH = 12.5

You can also learn about molarity from the following question:

brainly.com/question/14782315

#SPJ4

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1 year ago
PLZ HELP, GIVING BRAINLIEST!!
Veseljchak [2.6K]

Answer:

2.29 moles of Cr₂O₃ are produced

Explanation:

This is the reaction:

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Ratio for this equation is 4:2, so 4 moles of chromium can produce the half of moles of chromium(III) oxide

4.58 mol of Cr may produce (4.58  .2)/4 = 2.29 moles of Cr₂O₃

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3 years ago
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ValentinkaMS [17]
6.02 times 10 to the 23 power, which is Avogadros number 
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Phosphine, an extremely poisonous and highly reactive gas, will react with oxygen to form tetraphosphorus decaoxide and water. P
pantera1 [17]

Answer:

The mass of P₄O₁₀ (s) formed is 471.03 g

Explanation:

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This is the ballanced equation.

Every 4 moles of phosphine, 1 mol of tetraphosphorus decaoxide is generated.

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Molar mass  P₄O₁₀  = 283.88 g/m

1.66m  . 283.88 g/m = 471.03 g

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<span>- turning off the water while brushing your teeth.
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