When ΔG° is the change in Gibbs free energy
So according to ΔG° formula:
ΔG° = - R*T*(㏑K)
here when K = [NH3]^2/[N2][H2]^3 = Kc
and Kc = 9
and when T is the temperature in Kelvin = 350 + 273 = 623 K
and R is the universal gas constant = 8.314 1/mol.K
So by substitution in ΔG° formula:
∴ ΔG° = - 8.314 1/ mol.K * 623 K *㏑(9)
= - 4536
Answer:
glucose and oxygen
Explanation:
plants use carbondioxide, water and sunlight to produce their food through photosynthesis so in return they produce oxygen into the air as by product and glucose
Answer:
The answer to your question is V2 = 1.82 l
Explanation:
Data
Volume 1 = 77 l
Pressure 1 = 18 mmHg
Volume 2 = ?
Pressure 2 = 760 mmHg
Process
Use Boyle's law to solve this problem
P1V1 = P2V2
-Solve for V2
V2 = P1V1/P2
-Substitution
V2 = (18 x 77) / 760
-Simplification
V2 = 1386 / 760
-Result
V2 = 1.82 l
Answer:
CO(g) + 2H₂(g) → CH₃OH(l)
Explanation:
Carbon monoxide has molecular formula CO, molecular hydrogen has formula H₂, and methanol is CH₃OH.
The reactants are CO and H₂ and the product CH₃OH:
CO(g) + H₂(g) → CH₃OH(l)
To balance the equation, the elements must have the same amount on each side. C and O are balanced, but there is 4H in the product and only 2 in the reactant, so we multiply H₂ for 2:
CO(g) + 2H₂(g) → CH₃OH(l)
And the equation is balanced.
