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3 years ago

Using elimination method, simultaneously solve, 6x+2y=20 and 0.5x-0.5y=1

Mathematics

1 answer:

Aleksandr [31]3 years ago

8 0

Answer:

x=3, y=1. (3, 1)

Step-by-step explanation:

6x+2y=20

0.5x-0.5y=1

-----------------

6x+2y=20

1/2x-1/2y=1

----------------

6x+2y=20

2(1/2x-1/2y)=2(1)

------------------------

6x+2y=20

x-y=2

-------------------

6x+2y=20

x=y+2

---------------

6(y+2)+2y=20

6y+12+2y=20

8y+12=20

8y=20-12

8y=8

y=8/8

y=1

x=1+2=3

x=3, y=1.

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Find a formula for the general term an of the sequence, assuming that the pattern of the first few terms continues. (Assume that

mezya [45]

Answer:

The formula to the sequence

-5, 10/3, -20/9, 40/27, -80/81, ...

(-1)^n. 5×2^(n-1). 3^(1-n)

For n = 1, 2, 3, ...

Step-by-step explanation:

The sequence is

-5, 10/3, -20/9, 40/27, -80/81, ...

By inspection, we see the following

- The numbers are alternating between - and +

- The numerator of a number is twice the numerator of the preceding number. The first number is 5.

- The denominator of a number is 3 raised to the power of (1 minus the position of the number)

Using these, we can write a formula for the sequence.

(-1)^n for n = 1, 2, 3, ... takes care of the alternation between + and -

5×2^(n-1) for n = 1, 2, 3, ... takes care of the numerators 5, 10, 20, 40, ...

3^(1-n) for n = 1, 2, 3, ... takes care of the denominators 1, 3, 9, 27, ...

Combining these, we have the formula to be

(-1)^n. 5×2^(n-1). 3^(1-n)

For n = 1, 2, 3, ...

8 0

3 years ago

Thank you to whoever helps

MakcuM [25]

The answer is C because x2 is a parabola

5 0

3 years ago

3x+5+4x+6<br>simplify this

zloy xaker [14]

Just simply collect like terms.

3x+4x+5+6
7x+11

7 0

3 years ago

Read 2 more answers

One number is one-third a second number. if the sum of the numbers is 48, find the numbers.

Gnoma [55]

First number assume A

Second number assume B

A= 1/3B ==> B= 3A

A+B = 48 ==> A+ 3A= 48

4A= 48 ==> A= 12

B= 3A= 36

8 0

3 years ago

Solve for x use the completing the square method x^2+6x=5

Mrac [35]

Answer:

$x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}$

Step-by-step explanation:

$x^{2}$ +6x-5=0

we divide the coefficient of the X by half :

in this case: 6/2 = 3 , then we do the following

The result obtained is raised to square power: 3^2=9

we sum and subtract by 9 to maintain the balance of the equation:

$x^{2}$ +6x+9-9-5=0

we have:

$(x+3)^{2}$ -9-5=0

$(x+3)^{2}$ = 14

lets apply square root on both sides of the equation:

$\sqrt{(x+3)^{2}}=\sqrt{14}$

we know:

$\sqrt{a^{2}} = abs(a)$

so we have:

abs(x+3)= $\sqrt{14}$

from where two solutions are obtained

$x_{1} + 3 =\sqrt{14} \\\\x_{2} + 3 =-\sqrt{14}$

finally we have:

$x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}$

5 0

3 years ago

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Using elimination method, simultaneously solve, 6x+2y=20 and 0.5x-0.5y=1​

Using elimination method, simultaneously solve, 6x+2y=20 and 0.5x-0.5y=1