04:49

Question 5(A)
Answer:51
Explanation
Step 1:evaluate the power
Step2:add the numbers
Step 3:calculate the square root
Step4:reduce the fraction with 4
Step5:calculate the sum or the difference and ur final answer is 51

Question 5(B)
Answer:9/2
Explanation:
Step 1:calculate the difference
Step 2:evaluate the power
Step 3:subtract the numbers
Step 4:calculate the sum
And ur final answer is 9/2

Question 6:(A)
Answer:x=36/11
Explanation:
Step 1:distribute 4 through the parentheses
Step 2:move variable to the left hand side and change its sign
Step 3:move constant to the right hand side and Change it’s sign
Step 4:collect like items
Step 5:add the numbers
Step 6:divide both sides of the equation by 11
And ur final answer is x=36/11

Question 6(B)
Answer:x=192
Explanation:
Step 1:multiply both sides of the equation by 3
Step 2:move the constant to the right hand side and change its sign
Step 3:add the numbers
And ur final answer is x=192

Question 7
Answer B($60)
Explanation:the shape is rectangular and it is 12 feet long and the other is 5 feet wide it’s like finding the area of it so u basically need to multiply 12 by 5 and ur answer is 60

Here is the answers and the explanations step by step I hope it helps
Have a great day and stay safe

6 0

3 years ago

If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?

lys-0071 [83]

Answer:

2

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

$3x^2-(3k-2)x-(k-6) \text{ with }k=2$ :

$3x^2-(3\cdot 2-2)x-(2-6)$

$3x^2-4x+4$

I'm going to solve $3x^2-4x+4=0$ for x using the quadratic formula:

$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}$

$\frac{4\pm \sqrt{16-16(3)}}{6}$

$\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}$

$\frac{4\pm 4\sqrt{-2}}{6}$

$\frac{2\pm 2\sqrt{-2}}{3}$

$\frac{2\pm 2i\sqrt{2}}{3}$

Let's see if uv=u+v holds.

$uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}$

Keep in mind you are multiplying conjugates:

$uv=\frac{1}{9}(4-4i^2(2))$

$uv=\frac{1}{9}(4+4(2))$

$uv=\frac{12}{9}=\frac{4}{3}$

Let's see what u+v is now:

$u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}$

$u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}$

We have confirmed uv=u+v for k=2.

4 0

2 years ago

I am struggling with these questions. Please help

Sauron [17]

Answer: Just apply the formula

Step-by-step explanation:

The equation for volume of a cone is:

$V_{(cone)} =\frac{1}{3} \pi r^{2} h$

The radius is the line that creates a 90 degree angle with the height

The height goes from the base to the tip of the cone.

I recommend leaving Pi as it is and plugging the rest of the numbers first.

Then at the end multiply by 3.14 and round at the end.

This way, it is easier to avoid calculation errors.

5 0

3 years ago

Can anyone help me in Ptolemy's theorem?

GalinKa [24]

Answer:

Well, I'm not sure what you mean but Ptolemy's Theorem gives a relationship between the side lengths and the diagonals of a cyclic quadrilateral; it is the equality case of Ptolemy's Inequality. Ptolemy's Theorem frequently shows up as an intermediate step in problems involving inscribed figures.

8 0

2 years ago

Ased only on the information given in the diagram, which congruence theorems could be given as reasons why JOY ~ LIM? Check all

Nesterboy [21]

AAS and ASA are among the reasons.

6 0

3 years ago

Read 2 more answers