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Tamiku [17]
3 years ago
11

How many grams of oxygen gas will be produced when 2.50 moles of potassium chlorate is decomposed?

Chemistry
1 answer:
yawa3891 [41]3 years ago
8 0

Answer:

m_{O_2}=120gO_2

Explanation:

Hello!

In this case, since the decomposition of potassium chlorate is:

2KClO_3\rightarrow 2KCl+3O_2

We can see a 2:3 mole ratio between potassium chlorate and oxygen (molar mass 32.0 g/mol), thus, via stoichiometry, we compute the mass of oxygen that are produced by the decomposition of 2.50 moles of this reactant:

m_{O_2}=2.50molKClO_3*\frac{3molO_2}{2molKClO_3} *\frac{32.0gO_2}{1molO_2}\\\\m_{O_2}=120gO_2

Best regards!

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