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Tamiku [17]
2 years ago
11

How many grams of oxygen gas will be produced when 2.50 moles of potassium chlorate is decomposed?

Chemistry
1 answer:
yawa3891 [41]2 years ago
8 0

Answer:

m_{O_2}=120gO_2

Explanation:

Hello!

In this case, since the decomposition of potassium chlorate is:

2KClO_3\rightarrow 2KCl+3O_2

We can see a 2:3 mole ratio between potassium chlorate and oxygen (molar mass 32.0 g/mol), thus, via stoichiometry, we compute the mass of oxygen that are produced by the decomposition of 2.50 moles of this reactant:

m_{O_2}=2.50molKClO_3*\frac{3molO_2}{2molKClO_3} *\frac{32.0gO_2}{1molO_2}\\\\m_{O_2}=120gO_2

Best regards!

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A solution is prepared by dissolving 0.23 mol of hypochlorous acid and 0.27 mol of sodium hypochlorite in water sufficient to yi
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Answer:

hypochlorite ion

Explanation:

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HCl + ClO⁻ → HClO + Cl⁻.

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2 years ago
If 23.6 g of hydrogen gas reacts with 28.3 g of nitrogen gas, what is the maximum amount of product that can be produced?
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Answer:

34.3 g NH3

Explanation:

M(H2) = 2*1 = 2 g/mol

M(N2) = 2*14 = 28 g/mol

M(NH3) = 14 + 3*1 = 17 g/mol

23.6 g H2* 1 mol/2 g = 11.8 mol H2

28.3 g N2 * 1 mol/28 g = 1.01 mol N2

                                 3H2 + N2 ------> 2NH3

from reaction         3 mol    1 mol

given                   11.8 mol    1.01 mol

We can see that H2 is given in excess, N2 is limiting reactant.

                                 3H2 + N2 ------> 2NH3

from reaction                     1 mol         2 mol

given                                 1.01 mol      x

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3 years ago
Two different compounds are formed by the elements nitrogen and oxygen. The first compound, compound P1, contains 64.17% by mass
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Answer:

Explanation:

To solve the problem, we must know the kind of compounds we are dealing with.

For the first compound, P1 and second compound P2:

                                N                       O                         N                     O

Mass percent       64.17                 35.73                  47.23               52.79

Atomic mass          14                      16                         14                    16

Number of

moles            64.17/14            35.73/16            47.23/14    52.79/16      

                            4.58                  2.23                     3.37                  3.30

Simplest

ratio                 4.58/2.23            2.23/2.23             3.37/3.30         3.3/3.3

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P1 compound is N₂O

P2 compound is NO

These are the compounds,

   In N₂O = 28:16

          NO = 14:16

This is the ratio of nitrogen to a fixed mass of oxygen for the two compounds.

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