Question

The free-fall acceleration at the surface of planet 1 is 15 m/s2. The radius and the mass of planet 2 are twice those of planet 1. Part A What is g on planet 2

Answer 1

Answer:

3.75m/s²

Explanation:

g= GM/r²

For planet 1

$g_{1}$= GM/r²                   (i)

$g_{1}$ = 15m/s²

for planet 2

radius= 2*r= 2r

g= GM/r

$g_{2}$= GM/(2r)²

$g_{2}$= GM/4r²

$g_{2}$=  GM/r² *1/4

from (i)

$g_{2}$=  $g_{1}$ *1/4

$g_{2}$ = 15/4

$g_{2}$ = 3.75m/s²