Suppose that a passenger intent on lunch during his first ride in a hot-air balloon accidently drops an apple over the side duri
1 answer:
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Answer:
a = 9.81[m/s^2]; v = 18683.5[m/s]
Explanation:
The stament of the problem is:
Suppose that the man pictured on the front side is orbiting the earth (mass = 5.98 x 1024kg) at a distance of 310 miles (1600 meters = 1 mile) above the surface of the earth (radius = 4000 miles).
a. What acceleration does he experience due to the earth's pull?
b. What tangential velocity must he possess in order that he orbit safely (in m/s)?
First we need to convert all the initial data to units of the SI
Rs = 310 [mil] = 498897 [m]
RT= 400 [mil] = 643738 [m]
r = Rs + RT = 1142635 [m] "distance from the center of the earth to the man"
G = universal gravitational constant
M = mass of the earth [kg]
m = mass of the man [kg]
r = distance from the center of the earth to the man [m]
a)
The acceleration he is experimenting is the same acceleration given by the gravity, therefore:
a = g = 9.81[m/s^2]
b)
To find the tangential velocity, we must determinate the force exerted by the earth.
Now we will find the force exerted by the gravity when the man is orbiting the earth at distance r.
And this force will be equal to the following expression:
Complete Question
1. What is the linear speed of a point on the edge of a 0.30 m diameter grinding wheel rotating at 1600 rpm?
2. What is the acceleration of the point?
Answer:
1
2
Explanation:
From the question we are told that
The diameter is
The angular speed is
Generally the is mathematically represented as
Generally the linear speed is mathematically represented as
Generally the acceleration is mathematically represented as