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DiKsa [7]
3 years ago
10

You stand near the edge of a swimming pool and observe through the water an object lying on the bottom of the pool.

Physics
1 answer:
Alla [95]3 years ago
4 0

Answer:

a. The apparent depth of the object is less than the real depth.

Explanation:

When we observe for any object lying at the bottom of the pool from the edge of the pool then we are actually viewing an object from an optically rarer medium into an optically denser medium.

The schematic shows the apparent view of the object due to the bending of the rays coming form the object to our eyes.

The rays when coming from a denser medium to a rarer medium they bend away from the normal of the interface.

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Global warming will produce rising sea levels partly due to melting ice caps but also due to the expansion of water as average o
Setler79 [48]

Answer:

0.07 m

Explanation:

L_0 = Initial length = 1 km = 1000 m

\Delta T = Change in temperature =  1.00°C

\alpha = Coefficient of linear thermal expansion

Volumetric coefficient of expansion of water

\beta=210\times 10^{-6}^{\circ}C\\\Rightarrow \beta=3\alpha\\\Rightarrow \alpha=\dfrac{\beta}{3}\\\Rightarrow \alpha=\dfrac{210\times 10^{-6}}{3}\\\Rightarrow \alpha=70\times 10^{-6}\ ^{\circ}C

Change in length is given by

\Delta L=L_0\alpha \Delta T\\\Rightarrow \Delta L=1000\times 1\times 70\times 10^{-6}\\\Rightarrow \Delta L=0.07\ m

The change in length is 0.07 m

3 0
3 years ago
Please helppp.
cricket20 [7]

The answer is "True".


Please correct me if I'm wrong!! :)

6 0
4 years ago
Which of the following would not be considered a projectile?
Naddika [18.5K]

Answer:

e. All of the above are projectile

Explanation:

A projectile is an object with motion, aka a non-zero speed. A cannonball throwing straight up, rolling down a slope, rolling off the edge of a tale, thrown through the air have motion. They all have speed and kinetic energy. Therefore they can all be considered a projectile.

5 0
3 years ago
How strong an electric field is needed to accelerate electrons in an X-ray tube from rest to one-tenth the speed of light in a d
Bond [772]

Answer:

E= 50.1*10³ N/C

Explanation:

Assuming no other forces acting on the electron, if the acceleration is constant, we can use the following kinematic equation in order to find the magnitude of the acceleration:

vf^{2} -vo^{2}  = 2*a*x

We know that v₀ = 0 (it starts from rest),  that vf = 0.1*c, and that x = 0.051 m, so we can solve for a, as follows:

a = \frac{vf^{2}}{2*x} = \frac{(3e7 m/s)^{2} }{2*0.051m} =8.8e15 m/s2

According to Newton's 2nd Law, this acceleration must be produced by a net force, acting on the electron.

Assuming no other forces present, this force must be due to the electric field, and by definition of electric field, is as follows:

F = q*E (1)

In this case, q=e= 1.6*10⁻19 C

But this force, can be expressed in this way, according Newton's 2nd Law:

F = m*a (2) ,

where m= me = 9.1*10⁻³¹ kg, and a = 8.8*10¹⁵ m/s², as we have just found out.

From (1) and (2), we can solve for E, as  follows:

E=\frac{me*a}{e} =\frac{(9.1e-31 kg)*(8.8e15m/s2)}{1.6e-19C} = 50.1e3 N/C

⇒ E = 50.1*10³ N/C

3 0
4 years ago
Which value would complete the last cell?
GREYUIT [131]

Answer:

4.0

Explanation:

The following data were obtained from the question:

Force (F) = 20 N

Mass (m) = 5 kg

Acceleration (a) =.?

Force is simply defined as the product of mass and acceleration. Mathematically, it is expressed as

Force (F) = mass (m) x acceleration (a)

F = ma

With the above formula, we can obtain th acceleration of the body as follow:

Force (F) = 20 N

Mass (m) = 5 kg

Acceleration (a) =.?

F = ma

20 = 5 x a

Divide both side by 5

a = 20/5

a = 4 m/s²

Therefore, the value that will complete the last cell in the question above is 4.

5 0
4 years ago
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