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satela [25.4K]
3 years ago
10

When the Chili restaurant chain was in financial trouble.its CEO directed the managers of each of the chain's restaurant to trim

costs without sacrificingcustomer satisfaction.Which of the following did the CEO use to make restaurant managers accountable for cost-cutting measures?A) substitution8) transpositionC) delegation of authorityD) job sharing
Mathematics
1 answer:
Sloan [31]3 years ago
8 0

Answer: Option C : delegation of authority

Step-by-step explanation:

the CEO used DELEGATION OF AUTHORITY approach to make restaurant managers accountable for cost-cutting measures in the above case.

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Please help me with this
kondaur [170]
For number 1a. the answer is 7 to 26 or
7:26 or
\frac{7}{26}
For number 2a. the answer is 8 to 28 or
8:28 or
\frac{8}{28}  or    \frac{2}{7}
For number 3a. the answer is 12 to 13 or
12:13 or
\frac{12}{13}
For number 4a. the answer is 19 to 12 or
19:12 or
\frac{19}{12}
For number 5a. the answer is 29 to 10 or
29:10 or
\frac{29}{10}
For number 6a. the answer is 11 to 28 or
11:28 or
\frac{11}{28}

I just did your homework
4 0
3 years ago
The circle passes through the point (-1,-6). What is its radius?
love history [14]

Answer:

the radius is something in math

3 0
3 years ago
Read 2 more answers
Find the area of each figure
Anon25 [30]
Area of trapezoid = a + b/2 * h
a = 20, b = 9, h = 21/-16
20+9/2 * (21-16) = 29/2 * 5 = 72.5
The area of the trapezoid = 72.5 in^2

Area of the rectangle = l * w
l = 16, w = 20
16 * 20 = 320
The area of the rectangle: 320 in^2
7 0
3 years ago
(8x + 11) - (7x - 5)?​
zaharov [31]

Answer:

use the cymath calculator

Step-by-step explanation:

3 0
3 years ago
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<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B2%7D-5x%2B6%7D%7B2x%5E%7B2%7D-7x%2B6%20%7D" id="TexFormula1" title="\frac{x^{
il63 [147K]

Answer:

\frac{x-3}{2x-3}. hole or removable discontinuity at x=2

Step-by-step explanation:

Well generally if you want the simplest form, you factor each the denominator and numerator and then see if you can cancel any of the factors out (because they're in the denominator and numerator)

So let's start by factoring the first equation:

x^2-5x+6

Now let's find what ac is (it's just c since a=1...)

AC= 6

List factors of -6

\pm1, \pm2, \pm3, \pm6.

Now we have to look for two numbers that add up to -5. It's a bit obvious here since there isn't many factors, but it's -2 and -3, and they're both negative since 6 is positive, and -5 is negative...

So using these two factors we get

(x-2)(x-3)

Ok now let's factor the second equation:

2x^2-7x+6

Multiply a and c

AC = 12

List factors of 12:

\pm1, \pm2, \pm3, \pm4, \pm6, \pm12.

Factors that add up to -7 and multiply to 12:

-3\ and\ -4

Rewrite equation:

2x^2-4x-3x+6

Group terms:

(2x^2-4x)+(-3x+6)

Factor out GCF:

2x(x-2)-3(x-2)

Rewrite:

(2x-3)(x-2)

Now let's write out the equation using these factors:

\frac{(x-2)(x-3)}{(2x-3)(x-2)}.

Here we can factor out the x-2 and the simplified form is:

\frac{x-3}{2x-3}

So we can "technically" define f(2) using the most simplified form, but it's removable discontinuity, so it has a hole as x=2. since it makes (x-2) equal to 0 (2-2) = 0.

8 0
2 years ago
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