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3 years ago

Which kind of light is used to carry information through optical fibers?

Physics

1 answer:

ZanzabumX [31]3 years ago

3 0

Red light would be commonly used due to the longer wavelength

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If a wave hits a smooth surface at an angle of incidence of 40 degrees, the angle of reflection is

dem82 [27]

As the surface given is a smooth surface, we can use specular reflection. According to the law of specular reflection, the angle of incidence equals the angle of reflection, so it will also be 40°. Answer is A.

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3 years ago

Read 2 more answers

The vertical columns on the periodic table of elements are called groups.<br> O A. True<br> B. False

VashaNatasha [74]

Answer:

A. True

Explanation:

The vertical columns on the periodic table are called groups or families because of their similar chemical behavior.

Brainlist Pls!

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3 years ago

The speed of sound at sea level is normally about 340 m/s. A stationary fire alarm has a frequency of 15,000 Hz. An observer run

Musya8 [376]

Answer:

The velocity of the observer is 6.8 m/s

Explanation:

Doppler effect equation is given by the formula:

$f'=\frac{v+v_o}{v-v_s} f\\\\where\ f'\ is \ the\ observed \ frequency=15300\ Hz,v_o\ is\ the\ velocity\ of\ the\ observer,\\v_s\ is\ the\ velocity\ of \ source=0,v\ is\ the\ velocity\ of\ sound=340\ m/s\ and\ f\ is\ actual\\frequency=15000\ Hz.\\\\substituting:\\\\15300=15000(\frac{340+v_o}{340} )\\\\340+v_o=346.8\\\\v_o=6.8\ m/s$ The velocity of the observer is 6.8 m/s

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3 years ago

A proton is traveling horizontally to the right at 4.20×10^6m/s.Part A:Find (a)the magnitude and (b) direction of the weakest el

anygoal [31]

Answer:

2630250 N/C, horizontally left

$1.67\times 10^{-8}\ s$

1434.825 N/C, horizontally left

Explanation:

m = Mass of particle

u = Initial velocity = $4.2\times 10^6\ m/s$

v = Final velocity = 0

t = Time taken

s = Displacement = 3.5 cm

q = Charge of particle = $1.6\times 10^{-19}\ C$

Force is given by

$F=qE$

Acceleration is given by

$a=\dfrac{F}{m}\\\Rightarrow a=\dfrac{qE}{m}\\\Rightarrow a=\dfrac{1.6\times 10^{-19}\times E}{1.67\times 10^{-27}}\\\Rightarrow a=95808383.23353E$

$v^2-u^2=2as\\\Rightarrow v^2-u^2=2\times 95808383.23353Es\\\Rightarrow E=\dfrac{0^2-(4.2\times 10^6)^2}{2\times 95808383.23353\times 0.035}\\\Rightarrow E=-2630250\ N/C$

Magnitude of electric field is 2630250 N/C

Direction is horizontally to the left

The angle counterclockwise from left is zero.

$a=\dfrac{F}{m}\\\Rightarrow a=\dfrac{qE}{m}\\\Rightarrow a=\dfrac{1.6\times 10^{-19}\times -2630250}{1.67\times 10^{-27}}\\\Rightarrow a=-2.52\times 10^{14}\ m/s^2$

$v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{0-4.2\times 10^6}{-2.52\times 10^{14}}\\\Rightarrow t=1.67\times 10^{-8}\ s$

The time taken is $1.67\times 10^{-8}\ s$

Acceleration is given by

$a=\dfrac{F}{m}\\\Rightarrow a=\dfrac{qE}{m}\\\Rightarrow a=\dfrac{1.6\times 10^{-19}\times E}{9.11\times 10^{-31}}\\\Rightarrow a=175631174533.4797E$

$v^2-u^2=2as\\\Rightarrow v^2-u^2=2\times 175631174533.4797Es\\\Rightarrow E=\dfrac{0^2-(4.2\times 10^6)^2}{2\times 175631174533.4797\times 0.035}\\\Rightarrow E=-1434.825\ N/C$

Magnitude of electric field is 1434.825 N/C

Direction is horizontally to the left

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3 years ago

Which is the best estimate for the width of a typical adult hand?

Karo-lina-s [1.5K]

Answer:

About 4-5in

Explanation:

6 0

3 years ago