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evablogger [386]
3 years ago
6

A hot air balloon is ascending at a rate of 7.5m/s when a passenger drops a camera. If the camera is 25m above the ground when i

t is dropped, how much time does it take for the camera to reach the ground, and what is the velocity just before it lands?
Physics
1 answer:
Gemiola [76]3 years ago
5 0
The time it takes for an object to reach a certain level given the distance and the initial velocity can be calculated through the equation,

    d = V₀t + 0.5gt²

Where d is the distance, V₀ is the initial velocity, g is the acceleration due to gravity and t is time. Substituting the known values from the given above,

   25 = (-7.5)(t) + 0.5(9.8 m/s²)(t²)

The value of t from the equation 3.15s. Hence, it will take the object 3.15 seconds to reach the ground. 
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An 8.50 m long ladder leans against the side of a building. The ladder is initially inclined at an angle of 47.0° to the horizon
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The angle of the ladder inclined with respect to the horizontal after being moved a distance of 0.82 m closer to the building is 53.84°

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cos 47° = Adjacent side / 8.5

Adjacent side = Initial distance of base of ladder from the building = 5.8 m

Adjacent side 2 = Final distance of base of ladder from the building

Adjacent side 2 = 5.8 - 0.82 = 4.98 m

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θ_{2} = cos^{-1} ( 0.59 )

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The formula used above is one of trigonometric ratios. Trigonometric ratios can used only in a right angled triangle where one of the angles in at 90 degrees and the other two angles are less than 90 degrees.

Therefore, the angle of the ladder inclined with respect to the horizontal after being moved is 53.84°

To know more about trigonometric ratios

brainly.com/question/1201366

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