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ruslelena [56]
3 years ago
12

Find the acceleration of a car that can go from rest to 50 km/h in 13 s

Physics
1 answer:
ziro4ka [17]3 years ago
8 0

The acceleration of the car is 1.067 m/s^{2}.

<u>Explanation:</u>

Acceleration is the measure of change in velocity experienced by any object for a given time period. So it is determined as the ratio of difference in the velocity to the time period.

As here the initial velocity is stated as zero, so u = 0. And the final velocity is termed as 50 km/h. Then we have to determine the acceleration in 13 s. So here we have to convert the units as common units. Thus, 50 km/h should be converted to m/s as \frac{50*1000}{3600}=13.88 m/s

So now, the initial velocity u = 0 and final velocity v = 13.88 m/s and the time period is given as t = 13 s.

Acceleration = \frac{v-u}{t}=\frac{13.88-0}{13}=1.067 m/s^{2}

So the acceleration of the car is 1.067 m/s^{2}.

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The specific heat capacity of copper is three times the specific heat capacity of lead. Equal masses of copper and lead are heat
Papessa [141]

Answer:

Three times

Explanation:

The amount of heat added to a substance when its temperature is increased from T_1 to T_2 is given by

Q=mc(T_2-T_1)

c= specific heat capacity

m= mass of the substance

⇒Q∝c

that is if c is increased three times the amount of heat added is also increased three times. Therefore, the amount of heat added to the copper is three times the heat added to lead.

7 0
3 years ago
Help please can’t fail physics
bezimeni [28]

Answer:

2, less than the change in momentum

Explanation:

hope this helps!! :)

6 0
3 years ago
Read 2 more answers
A ball is dropped from a boat so that it strikes the surface of a lake with a speed of 16.5 ft/s. While in the water, the ball e
denis23 [38]
The initial velocity is
v(0) = 16.5 ft/s

While in the water, the acceleration is
a(t) = 10 - 0.\frac{dv}{dt} =10-0.8v \\\\  \frac{dv}{10-0.8v}=dt \\\\ \int_{16.5}^{v} \,  \frac{dv}{10-0.8v}  = \int_{0}^{t} dt \\\\ - \frac{1}{0.8} [ln(10-0.8v)]_{16.5}^{v}=t \\\\ ln \frac{10-0.8v}{-3.2}=-0.8t \\\\  \frac{0.8v -10}{3.2}  =e^{-0.8t} \\\\ 0.8v = 10 + 3.2e^{-0.8t} \\\\ v=12.5+4e^{-0.08t}

The velocity function is
v(t)=12.5+4e^{-0.8t}
It satisfies the condition that v(0) = 16.5 ft/s.
When t = 5.7s, obtain
v(5.7)=12.5+4e^{-0.8\times5.7} = 12.54 \, ft/s

The depth of the lake is
d=\int_{0}^{5.7} \, (12.5+4e^{-0.8t})dt \\\\ = 12.5(5.7)+ \frac{4}{(-0.8)}[e^{-0.8t}]_{0}^{5.7} \\\\ =71.25-5(0.0105-1) =76.198 \, ft

Answer:
The velocity at the bottom of the lake is 12.5 ft/s
The depth of the lake is 76.2 ft


7 0
3 years ago
Please help...<br> Describe energy transformations in your own words.
Fynjy0 [20]
Energy transformations is a process of an energy form transforming into a new form of energy. Like thermal energy, mechanical, etc. An example; when we eat; it turns from chemical energy to mechanical or electrical to heat. Like a plug and to activate a toaster.
7 0
3 years ago
I forgot to post the pic<br>But please help<br>just need answers​
r-ruslan [8.4K]

Answer:

1.127,56,000m

2. 347,600,000

3. 384,000

4. 200000000

5.  16,000,000cm

6. 36,000,000cm

7. 125,000m long, 400m deep, 1,500m wide

8. 11.18km/sec

9. 5,400,000

10.  2g

11. 1,200 mg to 2700 mg

12.   158000 kg

13. 450000000 mg

14.    23,000g to 90,000g

15.   40,000 ML

16.  1,000 ML

17.  26,600 KL

18. 1,558,000 L

19. 60 ML

20. 0.947

5 0
3 years ago
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