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ruslelena [56]
3 years ago
12

Find the acceleration of a car that can go from rest to 50 km/h in 13 s

Physics
1 answer:
ziro4ka [17]3 years ago
8 0

The acceleration of the car is 1.067 m/s^{2}.

<u>Explanation:</u>

Acceleration is the measure of change in velocity experienced by any object for a given time period. So it is determined as the ratio of difference in the velocity to the time period.

As here the initial velocity is stated as zero, so u = 0. And the final velocity is termed as 50 km/h. Then we have to determine the acceleration in 13 s. So here we have to convert the units as common units. Thus, 50 km/h should be converted to m/s as \frac{50*1000}{3600}=13.88 m/s

So now, the initial velocity u = 0 and final velocity v = 13.88 m/s and the time period is given as t = 13 s.

Acceleration = \frac{v-u}{t}=\frac{13.88-0}{13}=1.067 m/s^{2}

So the acceleration of the car is 1.067 m/s^{2}.

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Can someone explain how they got their answer or how I get the change in number? :(
enyata [817]

Answer:

See Below

Explanation:

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2 years ago
: A 70 kg man and a 12 kg sled are on the frictionless ice of a frozen lake, 25 m apart but connected by a rope of negligible ma
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Answer:

x_1 = 3.74m

Explanation:

given,

mass of man = 70 kg

mass of sled = 12 kg

F = m a_s

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a_m = \dfrac{8.2}{70}

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(0.12+0.68)t^2=50

t = \sqrt{\dfrac{50}{0.8}}

t = 7.90 s

x_1 = \dfrac{1}{2}a_ct^2

x_1 = 0.5\times 0.12 \times 7.90^2

x_1 = 3.74m

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