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ruslelena [56]
3 years ago
12

Find the acceleration of a car that can go from rest to 50 km/h in 13 s

Physics
1 answer:
ziro4ka [17]3 years ago
8 0

The acceleration of the car is 1.067 m/s^{2}.

<u>Explanation:</u>

Acceleration is the measure of change in velocity experienced by any object for a given time period. So it is determined as the ratio of difference in the velocity to the time period.

As here the initial velocity is stated as zero, so u = 0. And the final velocity is termed as 50 km/h. Then we have to determine the acceleration in 13 s. So here we have to convert the units as common units. Thus, 50 km/h should be converted to m/s as \frac{50*1000}{3600}=13.88 m/s

So now, the initial velocity u = 0 and final velocity v = 13.88 m/s and the time period is given as t = 13 s.

Acceleration = \frac{v-u}{t}=\frac{13.88-0}{13}=1.067 m/s^{2}

So the acceleration of the car is 1.067 m/s^{2}.

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The 0.5kg soccer ball moves toward the net with a force of 4N. What is its acceleration?​
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Answer:

8 m/s²

Explanation:

Given,

Force ( F ) = 4 N

Mass ( m ) = 0.5 kg

To find : -

Acceleration ( a ) = ?

Formula : -

F = ma

a = F / m

= 4 / 0.5

= 40 / 5

a = 8 m/s²

It's acceleration is 8 m/s².

6 0
3 years ago
A car starts from rest and travels for 5.8 s with a uniform acceleration of 1.6 m/s² in the negative direction. What is the fina
elena-s [515]

Answer:

Final velocity of the car will be -9.28 m/sec        

Explanation:

We have given that the car starts from the rest so initial velocity of the car u = 0 m /sec

Acceleration of the car a=1.6m/sec^2 in negative direction so acceleration will be a=-1.6m/sec^2

From first equation of motion we know that

v = u+at

So v=0+(-1.6)\times 5.8=-9.28m/sec

So final velocity will be -9.28 m/sec

8 0
3 years ago
Find the momentum of a 25 kg object traveling at a speed of 4 m/s
White raven [17]

Answer:

100 kg*m/s

Explanation:

P = m*v

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4 0
3 years ago
The head of a state government in the United States is referred to as which of the selections below?
nata0808 [166]

Answer:

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Explanation:

8 0
3 years ago
A sanding disk with rotational inertia 2.0 x 10-3 kg·m2 is attached to an electric drill whose motor delivers a torque of magnit
Inessa05 [86]

Answer

Given,

Rotational inertia = 2.0 x 10-3 kg·m²

Torque = 11 N.m

time, t = 19 ms

a) Angular momentum

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 L is angular momentum

  \Delta L = \tau \Delta t

  \Delta L = 11\times 19 \times 10^{-3}

  \Delta L = 0.209\ Kg m^2/s

b) Angular velocity

  We know.

     L = I \omega

     \omega = \dfrac{L}{I}

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     \omega = 104.5\ rad/s

4 0
3 years ago
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