A horizontal force of 93.7 N is applied to a 42.5 kg crate on a rough, level surface. If the crate accelerates at 1.03 m/s2, wha
1 answer:
Answer:
49.925N
Explanation:
According to newton's second law of motion:
is the sum of force along the x component
m is the mass of the crate
ax is the acceleration
Fk is the magnitude of the force of kinetic friction
Given
Fm = 93.7
m = 42.5kg
a = 1.03m/s²
Substitute into the formula:
Hence the magnitude of the force of kinetic friction (in N) acting on the crate is 49.925N
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