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pentagon [3]
3 years ago
5

A horizontal force of 93.7 N is applied to a 42.5 kg crate on a rough, level surface. If the crate accelerates at 1.03 m/s2, wha

t is the magnitude of the force of kinetic friction (in N) acting on the crate
Physics
1 answer:
vovangra [49]3 years ago
8 0

Answer:

49.925N

Explanation:

According to newton's second law of motion:

\sum Fx = ma_x

\sum Fx is the sum of force along the x component

m is the mass of the crate

ax is the acceleration

Fm - Fk = ma_x

Fk is the magnitude of the force of kinetic friction

Given

Fm = 93.7

m = 42.5kg

a = 1.03m/s²

Substitute into the formula:

93.7 - Fk = (42.5)(1.03)\\93.7-Fk = 43.775\\Fk = 93.7 - 43.775\\Fk = 49.925N

Hence the magnitude of the force of kinetic friction (in N) acting on the crate is 49.925N

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kupik [55]
The answer to this question would be: 1m/s

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When the burner in a hot air balloon is turned on, the temperature of the air in the balloon ________ causing its volume to ____
Georgia [21]

<u>Answer</u>

Part 1) Increase

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Part 3) rise


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3 years ago
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In the design of a supermarket, there are to be several ramps connecting different parts of the store. Customers will have to pu
tatuchka [14]

Answer:

3.90 degrees

Explanation:

Let g= 9.81 m/s2. The gravity of the 30kg grocery cart is

W = mg = 30*9.81 = 294.3 N

This gravity is split into 2 components on the ramp, 1 parallel and the other perpendicular to the ramp.

We can calculate the parallel one since it's the one that affects the force required to push up

F = WsinΘ

Since customer would not complain if the force is no more than 20N

F = 20

294.3sin\theta = 20

sin\theta = 20/294.3 = 0.068

\theta = sin^{-1}0.068 = 0.068 rad = 0.068*180/\pi \approx 3.90^0

So the ramp cannot be larger than 3.9 degrees

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The per-unit impedance of a single-phase electric load is 0.3. The base power is 500 kVA, and the base voltage is 13.8 kV. a. Fi
Leto [7]

Answer:

114.26

Explanation:

a)Formula for per unit impedance for change of base is

Zpu2= Zpu1×(kV1/kV2)²×(kVA2/kVA1)

Zpu2: New per unit impedance

Zpu1: given per unit impedance

kV1: give base voltage

kV2: New bas votlage

kVA1: given bas power

kVA2: new base power

In the question

Zpu2=??

Zpu1= 0.3

kV2=24kV

kV1= 13.8 kV

kVA2= 1MVA ×1000= 1000 kVA

kVA1=500kVA

Zpu2= 0.3(13.8/24)²×(1000/500)

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b) to find ohmic impedance we will first calculate base value of impedance(Zbase). So,

Zbase= kV²/MVA

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Now that we have base value of impedance, Zbase, we can calculate actual ohmic value of impedance(Zactual) by using the following formula:

Zpu=Zactual/Zbase

0.3= Zactual/380.88

Zactual= 114.26 ohms

8 0
3 years ago
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