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svp [43]
3 years ago
14

Developed an automated program in any language which take 12 dependent variable and corresponding independent variables and show

the output of least square regression in a form of relations.
Engineering
1 answer:
otez555 [7]3 years ago
3 0

Answer:

Explanation:

var generator = new Random(1);

// Now the nextGaussian() function returns a normal distribution of random numbers with the following parameters: a mean of zero and a standard deviation of one

var draw = function() {

var num = generator.nextGaussian();

var standardDeviation = 60;

var mean = 2003;

// Multiply by the standard deviation and add the mean.

var x = standardDeviation * num + mean;

noStroke();

fill(214, 159, 214, 10);

ellipse(x, 200, 16, 16); };

Hope this will be helpful

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How will you maintain the orderliness of your storage area 2pts?​
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Explanation:

Label and group products. One would think that a general cleanup would be the first step, but no, it's not. ...Clean up the area. ...Put up demarcation lines. ...Stack properly. ...Keep the aisles, paths and ramps clear. ...Have all the safety signs in place.

4 0
2 years ago
Please help!!!! WHICH 2 SKILLS N ABILITIES R ESSENTIAL FOR A SHIP CAPTAIN?? A. Good vision B. Public speaking skills C. Leadersh
Brilliant_brown [7]
A and C are the correct answers
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Select the correct answer.
andreev551 [17]

Answer:

c

Explanation:

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2 years ago
A girl operates a radio-controlled model car in a vacant parking lot. The girl's position is at the origin of the xy coordinate
lawyer [7]

Answer:

a) 17.20

b) 11.31

c) 14.42

d) 12.65

Explanation:

(a)

The girl is at the origin of the x,y coordinates  (i.e 0,0,0  )

the position vector of the car at time 't' secs is

\vec{r}= 2+2t^2, 6+t^3,0

at t=2s,  the position vector is

\vec{r}= 10, 14,0

Therefore, the the distance between the car and the girl is

s= \sqrt{(10-0)^2+(14-0)^2+(0-0)^2)}\

s = 17.20

(b)

The position of the car at  t = 0s is \vec{r}_0 = 2,6,0

The position of the car at t = 2s is \vec{r}_2 = 10,14,0

The distance of the car traveled in the interval from t=0s to t=2 s is as follows:

s_{02}= \sqrt{(10-2)^2+(14-6)^2+(0-0)^2)} \\ \\ s_{02}  = 11.31

(c)

The position vector of the car at time 't' secs is

\vec{r}= 2+2t^2, 6+t^3,0

The velocity of the car is

\vec{v}=\dfrac{d\vec{r}}{dt}= 4t, 3t^2,0

the direction of the car's velocity at t = 2s is  going to be

\vec{v}\mid _t=2 8, 12,0

Thus; The speed of the car is

v_{t=2}= \sqrt{8^2+12^2+0^2} \\ \\  v_{t=2}= 14.42

(d)    the car's acceleration is:

\vec{a}=\frac{d\vec{v}}{dt}= 4, 6t,0

The magnitude of car's acceleration at t=2s is

\mid \vec{a}\mid _{t=2}=\sqrt{4^2+12^2+0^2} \\ \\ \mid \vec{a}\mid _{t=2}= 12.65

5 0
3 years ago
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