Answer:
a) Friction factor for this duct = 0.0239
b) ε = 0.006 ft
Explanation:
Given data :
Flow rate = 11000 ft^3 /min
Pressure drop = 1.2 in per 1500 ft of duct
<u>a) Determine the value of the friction factor for this duct</u>
Friction factor for this duct = 0.0239
<u>b) Determine the approximate size of the equivalent roughness of the surface of the duct</u>
ε = 0.006 ft
attached below is the detailed solution to the given problem
Answer:
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Explanation:
Answer:
∆x = A / √2
Explanation:
If the mass is oscillating in a SHM, the total mechanical energy at any time is given by the following equation:
½ k A2 = ½ k (∆x)2 + ½ mv2
We are told that at the point that we are looking for, the elestic potential energy, and the kinetic energy, are equal each other.
As we have no information regarding kinetic energy, we can replace it with the equivalent in potential energy, so we have:
½ k (∆x)2 + ½ mv2 = 2 (1/2) k (∆x)2 = k (∆x)2
We know that this energy must be equal to ½ k A2, so we can put the following:
½ k A2 = k (∆x)2
Simplifying common terms, and solving for the displacement from the equilibrium point (∆x), we get:
∆x = A / √2
Explanation:
Answer:
a)mass flow=6lbm/s
b)the temperature at the compressor exit= 1269◦F
Explanation:
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To solve this problem we will perform the following steps
1.Use thermodynamic tables to find the density and entalpy of the air using the properties of temperature and pressure (2 psia and 77.3 ° F)
Density = 0.06032 lbm / ft ^ 3
h1=entalpy=351.2Btu/lbm
2.
Calculate the mass flow by multiplying the flow by the density, remember to apply conversion factors
3.We apply first law of thermodynamics in the compressor, it establishes that the energy that enters a system is the same that must come out.
Energies entering the compressor =
-Electric power (800hp)
=W=565.65btu/s
-flow energy (mh1)
energies coming out of the compressor
-heath= (Q)(m
)
-flow energy (mh2)
applying the above we have the following energy balance equation
W+mh1=Qm+mh2
Our goal is to determine the value of the enthalpy of output h2 in order to find the air temperature using thermodynamic tables
4.finally we use thermodynamic tables to find the temperature using enthalpy
T2=1269◦F
Answer:
0.124
Explanation:
We calculate the hydraulic gradient by the formulas below.
I = (change in h)/(change in l)-----eqn 1
I = (hk-hl)/change in L ----- equation 2
At k the headloss = hk,
At L the headloss = hL
The distance of water travel is change in I
Total head at k
hk = 543+23
= 566 ft
Total head at L
hL = 461+74
= 535 ft
Change in L = 250
When we substitute these values in equation 2
566-535/250
= 0.124
The hydraulic gradient is 0.124