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BabaBlast [244]
4 years ago
9

An inventor claims to have developed a power cycle operating between hot and cold reservoirs at 1175 K and 295 K, respectively,

that provides a steady-state power output of (a) 28 kW, (b) 31.2 kW, while receiving energy by heat transfer from the hot reservoir at the rate 150,000 kJ/h. Evaluate each claim
Engineering
1 answer:
Alinara [238K]4 years ago
4 0

Answer:

<em>a) efficiency is equal to 67.2%, and this is lesser than the maximum obtainable efficiency, so this power output is possible.</em>

<em>b) efficiency is 75%, this is approximately equal to the maximum obtainable efficiency, but not more that it. This power output is also possible.</em>

<em></em>

Explanation:

Cold reservoir temperature Tc = 295 K

Hot reservoir temperature Th = 1175 K

Energy input Q = 150000 K/h

Converting to kJ/s, Q  = 150000/3600 = 41.66 kJ/s

Maximum efficiency that can be obtained from this cycle = 1 - \frac{Tc}{Th}

==> 1 - \frac{295}{1175} = 0.748 ≅ 75%

also recall that actual cycle efficiency = \frac{W}{Q}

Where W is the energy output or work

a) for work of 28 kW,

eff =  \frac{W}{Q} =  \frac{28}{41.66} = 0.672 ≅ 67.2%

this is lesser than the maximum obtainable efficiency, so this power output is possible.

b) for work of 31.2 kW

eff =  \frac{W}{Q} =  \frac{31.2}{41.66} = 0.748 ≅ 75%

this is approximately equal to the maximum obtainable efficiency, but not more that it. This power output is possible.

NB: kW is also equal to kJ/S

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Dennis_Churaev [7]

Answer:

A)

- Q ( kw ) for vapor =  -1258.05 kw

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B )

- Q ( kj ) for vapor  = -1258.05 kJ

- Q ( KJ ) for liquid = - 1146.3 KJ

Explanation:

Given data :

45.00 % mole of methane

55.00 % of ethane

attached below is a detailed solution

A) calculate - Q(kw)

- Q ( kw ) for vapor =  -1258.05 kw

- Q ( kw ) for liquid = -1146.3 kw

B ) calculate  - Q ( KJ )

- Q ( kj ) for vapor  = -1258.05 kJ

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since combustion takes place in a constant-volume batch reactor

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Answer:

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6 0
3 years ago
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katen-ka-za [31]

Answer:

clc

clear

x = input('type value of angle in degrees:\n');

x = x*pi/180; %convverting fron degree to radian

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n = 0;

while E > 0.000001

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n = n+1;

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Explanation:

8 0
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Artyom0805 [142]

Answer:

C++ code explained below

Explanation:

Please note the below program has been tested on ubuntu 16.04 system and compiled using g++ compiler. This code will also work on other IDE's

-----------------------------------------------------------------------------------------------------------------------------------

Program:

-----------------------------------------------------------------------------------------------------------------------------------

//header files

#include<iostream>

//namespace

using namespace std;

//function defintion

void Output_Array_Info(int *array_ptr, int size)

{

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}

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{

cout<<array_ptr+i<<endl;

}

}

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return 0;

}

//end of the main program

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