Answer:
is the value of the equilibrium constant for this reaction at 756 K.
Explanation:
Equilibrium concentration of 
![[COCl_2]=7.40\times 10^{-4} M](https://tex.z-dn.net/?f=%5BCOCl_2%5D%3D7.40%5Ctimes%2010%5E%7B-4%7D%20M)
Equilibrium concentration of 
![[CO]=3.76\times 10^{-2} M](https://tex.z-dn.net/?f=%5BCO%5D%3D3.76%5Ctimes%2010%5E%7B-2%7D%20M)
Equilibrium concentration of 
![[Cl_2]=1.78\times 10^{-4} M](https://tex.z-dn.net/?f=%5BCl_2%5D%3D1.78%5Ctimes%2010%5E%7B-4%7D%20M)
The expression of an equilibrium constant can be written as;
![K_c=\frac{[CO][Cl_2]}{[COCl_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCO%5D%5BCl_2%5D%7D%7B%5BCOCl_2%5D%7D)
is the value of the equilibrium constant for this reaction at 756 K.
Answer: 1) only a salt and water
An acid and base reacts together to undergo neutralization to form salt and water.
where HCl is an acid and NaOH is a base to form salt (NaCl) and water 
.
Answer: 2) The formula of the hydrogen ion is often written as 
.
All acids dissociate in water to give ions.
Answer: 3) Arrhenius acids are substances that ionizes to yield protons in aqueous solution.
Arrhenius bases are substance that ionizes to yield hydroxide ions in aqueous solution.
Answer: 4) A conjugate acid base pair transfers hydrogen ion.
Here 
accepts a proton and thus act as a base and the corresponding 
is its conjugate acid.
Answer: 5) Bronsted Lowry acid is a substance that donates protons. Bronsted Lowry base is a substance that accepts protons.
and 
is a acid which accepts proton and thus acts as base to form conjugate acid .
We need an equation that would relate the concentration of the original solution to that of the desired solution. To solve this we use the equation expressed as follows,
M1V1 = M2V2
where M1 is the concentration
of the stock solution, V1 is the volume of the stock solution, M2 is the
concentration of the new solution and V2 is its volume.
M1V1 = M2V2
0.266 M x V1 = 0.075 M x 150 mL
V1 = 42.29 mL
Therefore, we need about 42.29 mL of the 0.266 M of lithium nitrate solution to make 150.0 mL of the 0.075 M lithium nitrate solution.
The chemical reaction is written as:
2Zn + O2 = 2ZnO
We are given the amount of the product to be produced from the reaction. We use this value and the relation of the substances in the reaction to calculate what is asked. We do as follows:
2.10 g ZnO ( 1 mol / 81.408 g ) ( 1 mol O2 / 2 mol ZnO ) ( 32 g / 1 mol ) = 0.414 g O2 is needed
