Answer:
The specific heat of the metal is 2.09899 J/g℃.
Explanation:
Given,
For Metal sample,
mass = 13 grams
T = 73°C
For Water sample,
mass = 60 grams
T = 22°C.
When the metal sample and water sample are mixed,
The addition of metal increases the temperature of the water, as the metal is at higher temperature, and the addition of water decreases the temperature of metal. Therefore, heat lost by metal is equal to the heat gained by water.
Since, heat lost by metal is equal to the heat gained by water,
Qlost = Qgain
However,
Q = (mass) (ΔT) (Cp)
(mass) (ΔT) (Cp) = (mass) (ΔT) (Cp)
After mixing both samples, their temperature changes to 27°C.
It implies that
, water sample temperature changed from 22°C to 27°C and metal sample temperature changed from 73°C to 27°C.
Since, Specific heat of water = 4.184 J/g°C
Let Cp be the specific heat of the metal.
Substituting values,
(13)(73°C - 27°C)(Cp) = (60)(27°C - 22℃)(4.184)
By solving, we get Cp =
Therefore, specific heat of the metal sample is 2.09899 J/g℃.
Place the mixture in hot water and stir well.
<span>The KNO3 is very soluble in hot water. </span>
<span>Use a fine filter paper and filter off the sand. </span>
<span>The sand will be separated from the KNO3 solution. </span>
<span>The water can now be evaporated from the solution by further, gentle heating leaving the solid in the container.</span>
Kinetic energy if it's based on temperature but potential energy is talking in terms of entropy
<h3>Answer:</h3>
36 moles of Hydrogen
<h3>Solution:</h3>
The molecular formula of Glucose is,
C₆H₁₂O₆
As clear from molecular formula, each mole of Glucose contains 12 moles of Hydrogen atoms.
Therefore,
1 mole of C₆H₁₂O₆ contains = 12 moles of Hydrogen
So,
3.0 moles of C₆H₁₂O₆ will contain = X moles of Hydrogen
Solving for X,
X = (3.0 mol × 12 mol) ÷ 1 mol
X = 36 moles of Hydrogen
