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Olin [163]
3 years ago
7

1. How many moles of CO2 can be produced from a reaction of 10.0 moles CzHg?

Chemistry
1 answer:
mr_godi [17]3 years ago
3 0

Answer:

20 moles of CO2 can be produced from a reaction of 10.0 moles C2H6

Explanation:

In this reaction -

2 moles of C₂H6 produces four molecules of Carbon dioxide (CO2)

So 1 mole of C₂H6 will produce \frac{4}{2} = 2 moles of Carbon dioxide (CO2)

Thus, 10 moles of C₂H6 will produce 2 * 10 = 20 moles of Carbon dioxide (CO2)

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How does a hydroelectric power plant convert energy?
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D. As water flows through the channels toward the turbines, it has kinetic energy. This is changed to mechanical energy as the water turns the turbines. Then the mechanical energy of the turbines is changed to electrical energy by the generator.

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A balloon containing 0.0400 mol of a gas with a volume of 500 mL was expanded to 1.00 L.
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b

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The electron configuration of an element is 1s22s22p63s1.
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The element is Sodium with an atomic number of 11 and electrovalent bonding takes place when it comes near an atom having seven valence electrons.

<h3>What is Electrovalent bonding?</h3>

This is also referred to as ionic bonding and involves the transfer of atoms of an element to another.

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2 years ago
Name the two possible products in the precipitation reaction of copper (II) chloride and sodium phosphate. Use the charges on th
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Answer:

General equation for a double-displacement reaction:  

AB + CD --> AC + BD

• sodium chloride – NaCl copper sulfate – CuSO₄  

NaCl + CuSO₄ --> Na₂SO₄ + CuCl₂

The products formed are sodium sulfate and copper (II) chloride.

Copper (II) chloride forms a blue colored solution.

• sodium hydroxide – NaOH copper sulfate – CuSO₄  

NaOH + CuSO₄ --> Na₂SO₄ + Cu(OH)₂

The products formed are sodium sulfate and copper (II) hydroxide.

Copper (II) hydroxide forms a blue colored solution.

• sodium phosphate – Na₂HPO₂ copper sulfate – CuSO₄  

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The products formed are sodium sulfate and copper (II) hydrogen phosphate.

Copper (II) hydrogen phosphate forms a blue colored solution.

• sodium chloride – NaCl silver nitrate – AgNO₃  

NaCl + AgNO₃--> AgCl + NaNO₃

The products formed are silver chloride and sodium nitrate.

Silver chloride forms a white precipitate.

• sodium hydroxide – NaOH silver nitrate – AgNO₃  

NaOH + AgNO₃   --> NaNO₃ + AgOH

The products formed are silver hydroxide and sodium nitrate.

Silver hydroxide forms a white precipitate.

• sodium phosphate – Na₂HPO₄ silver nitrate – AgNO₃

Na₂HPO₄ + AgNO₃  --> NaNO₃ +  Ag₂HPO₄

The products formed are sodium nitrate and silver hydrogen phosphate.

Silver hydrogen phosphate forms a colorless solution.

Explanation:

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