Explanation:
The similarities between chemical and physical changes include change in state of matter and both process involve change in energy.
Chemical changes of a substance results in the formation of entirely new substances. These changes are not reversible.
Physical changes results in the change of the state of the substance which can be reversed.
However, both chemical and physical changes results in change of state of matter and both process results in change in energy.
Thus, we can conclude that the similarities between chemical and physical changes include change in state of matter and both process involve change in energy.
(it's alre answered but here it again 'NOTE: not my answer')
Answer:
The correct option is;
Placing one drop of food coloring in a cup with 60 ml of water at 10°, placing one drop of food coloring in a second cup with 60 ml of water at 40°C
Explanation:
The experimental setup that would allow the student investigate the connection between kinetic energy and temperature should be made up of the following characteristics
1) The constant terms for the experiment should be defined, which in this case are
a) The volume of the water which is 60 ml in both subjects of the experiment
2) The definition of the variable that produces the effect that is being monitored, which is the use of the different temperatures in the two experimental subjects
3)The environmental limits of the experiment, which is the water and the food coloring used
The answer is BaO
hope this helpsssss
Answer:
The volume of the gas is approximately 4.41 liters
Explanation:
The details of the data of the Neon gas are;
The number of moles of Neon gas present, n = 11.6 moles
The temperature of the sample of Neon gas, T = 120 K
The pressure of the sample of the Neon gas, P = 25.6 atm
By the ideal gas equation, we have;
P·V = n·R·T
Where;
R = The universal gal constant = 0.08205 L·atm·mol⁻¹·K⁻¹
Therefore, we get;
V = n·R·T/P
Which gives;
V = 11.6 moles × 0.08205 L·atm·mol⁻¹·K⁻¹ × 120 K/(25.9 atm) ≈ 4.4097915 L
The volume of the gas, V ≈ 4.41 L.
