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3 years ago

"An acute angle is an angle smaller than a right angle."

Mathematics

1 answer:

love history [14]3 years ago

6 0

Answer:

<u>C. definition</u>

<u>Step-by-ste</u>p explanation:

"An acute angle is an angle smaller than a right angle or 90 degrees angle . this is the definition of acute angle

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Vikki [24]

Answer:

Step-by-step explanation:

Are there any answer choices?

8 0

3 years ago

Which must be true in order for the relationship △ZYV ~ △XWV to be correct?

tigry1 [53]

Hey there!

In order for two figures to be congruent, each named angle must correspond and be congruent to ONE other angle. If you have ZYV and XWV, Z must be congruent to X as they both show up first in the ordering.

This means...

∠Z≅∠X

∠Y≅∠W

∠V≅∠V

Our first answer option has to do with parallelism, which does not influence if certain angles are congruent or not.

For the second answer option, ∠Z is congruent to ∠X, not ∠Y, so it is incorrect.

For the third answer option, it shows that ∠Z would correspond to ∠V, but it does not, so it is also incorrect.

For D, ∠Z IS congruent to ∠X, and ∠W IS congruent to ∠Y

Therefore, our answer is D) ∠Z≅∠X and ∠W ≅ ∠Y.

I hope this helps!

3 0

3 years ago

Read 2 more answers

In a major hurry to finish this I was stuck doin other homework last year please help me finish this

Irina-Kira [14]

2 = m ≤ −9

3 = p ≥ 5

4 = x < -10

5 = b < -10

6 = n < 5

7 = n < 6

8 = r ≤ 4

9 = x ≥ 9

10 = p ≤ 0

11 = x < 1

12 = a > 24

6 0

3 years ago

Hiiiiooo❤️Can someone please help me out with my question

marin [14]

The answer is D. 50 because x equals 7 so if you fill that in for 4x-3 and multiply it by 2, you get 50

8 0

3 years ago

Read 2 more answers

A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe

adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

$\frac{dC}{dt}=Ci*Qi-Co*Qo$

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

$\frac{dC}{dt}=-Co*Qo$

Rearranging the equation, it becomes

$\frac{dC}{C}=-Qo*dt$

Integrating both sides

$\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}$

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

$C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\$

The final equation for the concentration of salt at any given time is

$C=exp^{-3*t-0.693}$

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

$C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}= -\frac{-0.266}{3}=0.088$

5 0

3 years ago