Answer:
Front and the rear bumpers.
Explanation:
When two license plates are issued they need to be attached to the Front and the rear bumpers of the vehicle they were issued for.
This type of system is an example of open system because the vapors leave the system and goes into the atmosphere.
<h3>
What is open system?</h3>
An open system is a type of system that has external interactions which means energy, or material transfers into or out of the system.
So we can conclude that this type of system is an example of open system because the vapors leave the system and goes into the atmosphere.
Learn more about system here: brainly.com/question/14323743
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The number of charge drifts are 3.35 X 10⁻⁷C
<u>Explanation:</u>
Given:
Potential difference, V = 3 nV = 3 X 10⁻⁹m
Length of wire, L = 2 cm = 0.02 m
Radius of the wire, r = 2 mm = 2 X 10⁻³m
Cross section, 3 ms
charge drifts, q = ?
We know,
the charge drifts through the copper wire is given by
q = iΔt
where Δt = 3 X 10⁻³s
and i = 
where R is the resistance
R = 
ρ is the resistivity of the copper wire = 1.69 X 10⁻⁸Ωm
So, i = 
q = 
Substituting the values,
q = 3.14 X (0.02)² X 3 X 10⁻⁹ X 3 X 10⁻³ / 1.69 X 10⁻⁸ X 0.02
q = 3.35 X 10⁻⁷C
Therefore, the number of charge drifts are 3.35 X 10⁻⁷C
Answer:
Explanation:
Start with Carbon and assume we only get 1 sugar molecule from the process.
you have 6 carbons in the sugar on the right, so you need 6 carbons on the left which only come from CO₂
6 CO₂
you have 12 hydrogen atoms in the sugar on the right, so you need 12 hydrogen atoms on the left which only come from H₂O. At 2 hydrogen atoms per water molecule means you need 6 waters.
6 CO₂ + 6 H₂O → 1 C₆H₁₂O₆
you are supplied with 12 oxygen from the CO₂ and 6 oxygen from the H₂O, but you only need 6 oxygen for the sugar. That means there are 12 oxygen remaining which will become 6 O₂ molecules
6 CO₂ + 6 H₂O → 1 C₆H₁₂O₆ + 6 O₂
Answer:
500m/s
Explanation:
From the question we are given the following;
mass per unit length = 4.80 x10^-3 kg/m
Tension T = 1200N
Speed of the wave is expressed as;
v = √T/m
v = √1200/0.0048
v = √250,000
v = 500m/s
Hence the speed at which the wave travels on this string is 500m/s
