Formula for terminal
velocity is:
Vt = √(2mg/ρACd)
<span>Vt = terminal velocity = ?
<span>m = mass of the falling object = 72 kg
<span>g = gravitational acceleration = 9.81 m/s^2
<span>Cd = drag coefficient = 0.80
<span>ρ = density of the fluid/gas = 1.2 kg/m^3</span>
<span>A = projected area of the object (feet first) = 0.21 m * 0.41
m = 0.0861 m^2
Therefore:</span></span></span></span></span>
Vt = √(2 * 72
* 9.81 / 1.2 * 0.0861 * 0.80)
<span>Vt = 130.73 m/s</span>
The image of the water tower and the houses is in the attachment.
Answer: (a) P = 245kPa;
(b) P = 173.5 kPa
Explanation: <u>Gauge</u> <u>pressure</u> is the pressure relative to the atmospheric pressure and it is only dependent of the height of the liquid in the container.
The pressure is calculated as: P = hρg
where
ρ is the density of the liquid, in this case, water, which is ρ = 1000kg/m³;
When it is full the reservoir contains 5.25×10⁵ kg. So, knowing the density, you know the volume:
ρ = ![\frac{m}{V}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7BV%7D)
V = ρ/m
V = ![\frac{5.25.10^{5}}{10^{3}}](https://tex.z-dn.net/?f=%5Cfrac%7B5.25.10%5E%7B5%7D%7D%7B10%5E%7B3%7D%7D)
V = 525 m³
To know the height of the spherical reservoir, its diameter is needed and to determine it, find the radius:
V = ![\frac{4}{3}.\pi.r^{3}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D.%5Cpi.r%5E%7B3%7D)
![r = \sqrt[3]{ \frac{3}{4\pi } .V}](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3%7D%7B4%5Cpi%20%7D%20.V%7D)
r = ![\sqrt[3]{\frac{525.3}{4\pi } }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B525.3%7D%7B4%5Cpi%20%7D%20%7D)
r = 5.005 m
diameter = 2*r = 10.01m
(a) Height for House A:
h = 15 + 10.01
h = 25.01
P = hρg
P = 25.01.10³.9.8
P = 245.10³ Pa or 245kPa
(b) h = 25 - 7.3
h = 17.71
P = hρg
P = 17.71.1000.9.8
P = 173.5.10³ Pa or 173.5 kPa
I don't think the shaping of the beach or hill would be considered
weathering, especially since it says "as smaller particles are moved
away". This one is just talking about where the particles decide to
gather and make a shape.
'C' is really talking about weathering, where rocks are broken up into
stones, and the stones into smaller pieces that can be blown away
on the wind. THAT's weathering.
The phrase "scientific knoledge" in the question is spelled correctly.
To solve this problem we apply the concepts related to the electric torque generated by the electromagnetic field. Mathematically this Torque can be written under the following relation
![\tau = NIAB sin\theta](https://tex.z-dn.net/?f=%5Ctau%20%3D%20NIAB%20sin%5Ctheta)
Here,
N = Number of Turns
I = Current
A = Area
B = Magnetic Field
The maximum torque will be reached when the angle is 90 degrees, then we will have the following relation,
![\theta = 90\°C](https://tex.z-dn.net/?f=%5Ctheta%20%3D%2090%5C%C2%B0C)
Magnetic Field is given at function of the number of loops, permeability constant at free space at the perimeter, then
![B = \frac{N\mu_0 I}{2\pi r}](https://tex.z-dn.net/?f=B%20%3D%20%5Cfrac%7BN%5Cmu_0%20I%7D%7B2%5Cpi%20r%7D)
![B = \frac{(60)(4\pi * 10^{-7})(4.2)}{2\pi (0.1)}](https://tex.z-dn.net/?f=B%20%3D%20%5Cfrac%7B%2860%29%284%5Cpi%20%2A%2010%5E%7B-7%7D%29%284.2%29%7D%7B2%5Cpi%20%280.1%29%7D)
![B = 5.04*10^{-4}T](https://tex.z-dn.net/?f=B%20%3D%205.04%2A10%5E%7B-4%7DT)
Replacing at the first equation we have,
![T = (20)(\pi (0.005)^2)(1)(5.04*10^{-4})](https://tex.z-dn.net/?f=T%20%3D%20%2820%29%28%5Cpi%20%280.005%29%5E2%29%281%29%285.04%2A10%5E%7B-4%7D%29)
![T = 7.91*10^{-7}N\cdot m](https://tex.z-dn.net/?f=T%20%3D%207.91%2A10%5E%7B-7%7DN%5Ccdot%20m)