Take east to be the positive direction. Then the resultant force from adding <em>F</em>₁ and <em>F</em>₂ is
<em>F</em>₁ + <em>F</em>₂ = (-45 N) + 63 N = 18 N
which is positive, so it's directed east.
To this we add a third force <em>F</em>₃ such that the resultant is 12 N pointing west, making it negative, so that
18 N + <em>F</em>₃ = -12 N
<em>F</em>₃ = -30 N
So <em>F</em>₃ has a magnitude of 30 N and points west.
Answer:
Force is 14.93N along positive y axis.
Explanation:
We know that force 'F' on a current carrying conductor placed in a magnetic field of intensity B is given by

where L is the length of the conductor
Applying values in the equation we have force F =

Thus force is 14.93N along positive y axis.
Complete Question
The complete question is shown on the first uploaded image
Answer:
The answer is a
Explanation:
The explanation is shown on the second uploaded image
Bro I really think it might be c
a. 27
after that all you need to do is use the work formula as you will be able to acheive results