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Mrac [35]
2 years ago
14

A small car and a large heavier bus are traveling at the same speed. Which has more momentum?

Physics
1 answer:
lions [1.4K]2 years ago
7 0

Answer:

small car since they weigh less than a bus

Explanation:

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counter question if you get out the shower clean then how does your towel get dirty?

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Which statement correctly compares ultraviolet light to visible light? Ultraviolet light has both a lower frequency and longer w
Effectus [21]

The correct statement is

Ultraviolet light has both a higher frequency and a higher radiant energy than visible light.

because ultraviolet light has wavelength smaller than the visible light hence has a greater frequency as compared to visible light. (frequency is inversely related to wavelength. hence smaller the wavelength , greater will be the frequency)

we also know that the radiant energy is directly proportional to the frequency. hence greater the frequency , greater will be the radiant energy.

Since the frequency is greater for ultraviolet light , it radiant energy is also greater


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3 years ago
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if the velocity of a car is halved the fc required to keeo it in a path of constant radius is multiplied/divided by?
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I believe this is it
The centripetal force is given by
F = mv^2 / r
When v' = v/2,
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So the centripetal force is divided by 4.
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3 years ago
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A 1800-kg Jeep travels along a straight 500-m portion of highway (from A to B) at a constant speed of 10 m/s. At B, the Jeep enc
vladimir1956 [14]

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4 0
2 years ago
What is the change in potential energy if the distance separating the electron and proton is increased to 1.0 nm?
Vlada [557]

Answer:

Ep=-2.3*10^{-19}J

Explanation:

The change in potential energy can be expressed as:

Ep=K.\frac{q1.q2}{r}

where K is a constant with a value of 9*10^{9}\frac{N.m^{2}}{C^{2}}, q1 and q2 are the charges of the proton and the electron and r is the distance between them.

The charge for the proton is +1.6*10^{-19}C and the charge for the electron is -1.6*10^{-19}C.

Converting r=1.0nm to m:

1.0nm*\frac{1*10^{-9}m}{1.0nm}=1*10^{-9}m

Replacing values:

Ep=9*10^{9}\frac{N.m^{2}}{C^{2}}.\frac{(+1.6*10^{-19}C).(-1.6*10^{-19}C)}{1*10^{-9}m}

Ep=-2.3*10^{-19}J

5 0
2 years ago
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