The coordinates of the dilated vertex V' is (-6p, 5p)
Transformation is the movement of a point from its initial location to a new location. Types of transformation are <em>translation, reflection, rotation and dilation.</em>
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Dilation is the increase or decrease in the size of a figure. If a point A(x, y) is dilated by a factor k, the new point is A'(kx, ky).
The Parallelogram TUVW has vertices at T(3, 4), U(-10,-2), V(-6,5) and W (7,11). If it is dilated by a scale factor p with the origin, the new point is at:
T'(3p, 4p), U'(-10p, -2p), V'(-6p, 5p) and W'(7p, 11p)
Find out more on dilation at:brainly.com/question/10253650
I'm guessing it is 10? or 7?
Answer:
225
Step-by-step explanation:
Answer:
(4×x) 7> 80 :)
Step-by-step explanation:
<span>Let r(x,y) = (x, y, 9 - x^2 - y^2)
So, dr/dx x dr/dy = (2x, 2y, 1)
So, integral(S) F * dS
= integral(x in [0,1], y in [0,1]) (xy, y(9 - x^2 - y^2), x(9 - x^2 - y^2)) * (2x, 2y, 1) dy dx
= integral(x in [0,1], y in [0,1]) (2x^2y + 18y^2 - 2x^2y^2 - 2y^4 + 9x - x^3 - xy^2) dy dx
= integral(x in [0,1]) (x^2 + 6 - 2x^2/3 - 2/5 + 9x - x^3 - x/3) dx
= integral(x in [0,1]) (28/5 + x^2/3 + 26x/3 - x^3) dx
= 28/5 + 40/9 - 1/4
= 1763/180 </span>
