Answer:
1296√3 cubic units
Step-by-step explanation:
The volume of the prism will be the product of its base area and its height. Since it circumscribes a sphere with diameter 12, that is the height of the prism.
The central cross section of the sphere is a circle of radius 6, and that will be the size of the incircle of the base. That is, the base will have an altitude of 3 times that incircle radius, and an edge length of 2√3 times that incircle radius. Hence the area of the triangular base is ...
B = (1/2)(6×2√3)(6×3) = 108√3 . . . . . square units
The volume of the prism is then ...
V = Bh = (108√3)(12) = 1296√3 . . . cubic units
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<em>Comment on the geometry</em>
The centroid of an equilateral triangle is also the incenter and the circumcenter. The distance of that center from any edge of the triangle is 1/3 the height of the triangle. So, for an inradius of 6, the triangle height is 3×6 = 18. The side length of an equilateral triangle is 2/√3 times the altitude, so is 12√3 units for this triangle.
Answer:
(D) "...because he will not have to pay any interest on his purchases during the introductory APR period."
Step-by-step explanation:
There may be many reasons for John to choose one over the other depending on his future and planned usage patterns. However, answer the (D) is the only correct one in terms of stating a reason that is actually supported by the information in the question. Specifically, there is 0% APR for card B.
What's wrong with the other choices:
Choice A: incorrect statement re APR after intro period (is not 1%); B: incorrect statement re cash advance (is not 0%); C: statement is not supported by anything in the information given (it is an assumption, and is unlikely).
1 liter: 1000 ml
so 2 liters: 2000 ml. s
so now the last step adding- 2000+500= 2500
so Dave made 2500 millimeters of punch
Answer:
-86
Step-by-step explanation:
3*5-(1+10^2)
15-(1+100)
15-101
-86
Area = 625 cm^2
Area = s^2
Diagonal = s*sqrt(2)
625 = s^2
s = sqrt(625)
s = 25 cm.
Diagonal = s*sqrt(2)
= 25sqrt(2)
=35.36 cm.
=35.4 cm.
