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storchak [24]
3 years ago
9

Guys please help me with this question!

Chemistry
1 answer:
damaskus [11]3 years ago
3 0
A reducing agent is one which is oxidised in the reaction itself. When you take into account the oxidation numbers you will see that the Cl- ions are oxidised from an oxidation number of -1 to 0 in Cl2. Therefore Cl- ions are the reducing agent.
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Which of the following happens when an ionic bond is formed? (1 point)
bazaltina [42]

This problem is asking for an explanation of what happens when an ionic bond is formed. Although the choices are not given in the question, one can find them on the attached file and realize the answer is C "a less electronegative atom donates an electron to a more electronegative atom" according to:

<h3>Types of bonds:</h3><h3 />

In chemistry, the forces that hold atoms together are known as chemical bonds and act like connections for atoms to form compounds. There exist ionic and covalent bonds, so the formers occur when electrons are thoroughly donated from the least electronegative atom to the most electronegative one.

On the flip side, covalent bonds occur when the electrons are shared between the two or more of the atoms forming the compound. In such a way, one can discard choices A and B because they are more related to covalent bonds.

Therefore, one can select C "a less electronegative atom donates an electron to a more electronegative atom" as the correct answer, because not all the elements are able to donate more than one single electron, and the less its valency, the more ionic the compound turns out to be.

Learn more about types of bonds: brainly.com/question/792566

3 0
3 years ago
If 13.7 grams of manganese oxide reacts with excess hydrogen chloride gas, how many grams of water are formed?
Lerok [7]

Answer:

5.67 g OF WATER WILL BE FORMED WHEN 13.7 g OF MnO2 REACTS WITH HCl GAS.

Explanation:

EQUATION FOR THE REACTION

Mn02 + 4HCl --------> MnCl2 + Cl2 + 2H2O

From the balanced reaction between manganese oxide and hydrogen chloride gas;

1 mole of MnO2 reacts to form 2 mole of water

At STP, the molecular mass of the sample is equal to the mole of the substance. So therefore:

(55 + 16 * 2) g of MnO2 reacts to form 2 * ( 1 *2 + 16) g of water

(55 + 32) g of MnO2 reacts to form 2 * 18 g of water

87 g of MnO2 reacts to form 36 g of water

If 13.7 g of MnO2 were to be used?

87 g of MnO2 = 36 g of H2O

13.7 g of MnO2 = ( 13.7 * 36 / 87) g of water

= 493.2 / 87 g of water

Mass of water = 5.669 g of water

Approximately 5.67 g of water will be formed when 13.7 g of manganese oxide reacts with excess hydrogen chloride gas.

3 0
3 years ago
Rewrite the function from vertex form to standard form. Then use either form to calculate f(1) and f(-1).
jonny [76]

Answer:

Standard form: (x+3)^2=1/2(y+3)

f(1) = 29

f(-1) = 5

Explanation:

The standard form of a parabola with a directrix that is horizontal is

(x-h)=4(P)(y-k)

Using the vertex form, find the vertex, foci, and the distance from the vertex to the focus or directrix.

It's easier to use the vertex form to plug in values for x.

f(1) = 2((1)+3)^2-3

f(1) = 29

f(-1) = 2((-1)+3)^2-3

f(-1) = 5

6 0
4 years ago
The CO2 produced in one round of the citric acid cycle does not originate in the acetyl carbons that entered that round. If the
aleksley [76]

Answer:

It will require<u> second round</u> of the cycle to release 14C0_2

Explanation:

<u>Reason behind the requirement of second round of the cycle to release </u>CO_2 -:

The C4 carbon of succinyl CoA is acetyl from acetyl CoA. Succinyl CoA is converted to succinate, which is then converted to fumarate, fumarate, malate, and eventually oxaloacetate. 14C will be found in oxaloacetate at either C1 or C4. During the second round of the loop, each of these carbons will be converted to carbon dioxide.

7 0
3 years ago
Which element will chemically combine with fluorine to combine salt?
Natali5045456 [20]

Answer:

When an atom of sodium and an atom of fluorine combine to form the salt, sodium fluoride, an ionic bond, is formed.

Explanation:

8 0
3 years ago
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