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GREYUIT [131]
2 years ago
5

How many molecules are in 0.73 mol of C12H22011? *

Chemistry
1 answer:
lbvjy [14]2 years ago
3 0

Answer:

C12h22o11 moles to grams

1 mole is equal to 1 moles C12H22O11, or 342.29648 grams.

hope this helps

Explanation:

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Nitrogen and hydrogen combine at a high temperature, in the presence of a catalyst, to produce ammonia. N 2 ( g ) + 3 H 2 ( g )
Kisachek [45]

Answer:

After complete reaction, 0.280 moles of ammonia are produced

Explanation:

Step 1: Data given

Number of moles N2 = 0.140 moles

Number of moles H2 = 0.434 moles

Step 2: The balanced equation

N2(g) + 3H2 (g) ⟶ 2NH3 (g)

Step 3: Calculate the limiting reactant

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

N2 is the limiting reactant. It will completely be consumed (0.140 moles).

H2 is in excess. There will react 3*0.140 = 0.420 moles

There will remain 0.434 - 0.420 = 0.014 moles

Step 4: Calculate moles NH3

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After complete reaction, 0.280 moles of ammonia are produced

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3 years ago
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As a chlorine atom becomes a negative ion, the atom blanks an electron
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Answer: increases by

As a chlorine atom becomes a negative ion, the atom "increases by" an electron

Explanation:

Chlorine atom has an atomic number of 17, and an electronic configuration of 1s2, 2s2 2p6, 3s2 3p5 showing 7 valence electrons in its outermost shell.

Hence, it receives a single electron to achieve a stable octet structure with electronic configuration of

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Cl + e- --> Cl-

Thus, as a chlorine atom becomes a negative ion, the atom "increases by" an electron

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3 years ago
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