Gases take the shape of their container and have no definite volume because they can diffuse indefinitely. Answer C.
Answer:
A) [H3PO4] will increase, [KH2PO4] will decrease, and pH will slightly decrease.
Explanation:
A buffer is a solution which resists changes to its pH when a small amount of acid or base is added to it.
Buffers consist of a weak acid (HA) and its conjugate base (A–) or a weak base and its conjugate acid. Weak acids and bases do not completely dissociate in water, and instead exist in solution as an equilibrium of dissociated and undissociated species. When a small quantity of a strong acid is added to a buffer solution, the conjugate base, A-, reacts with the hydrogen ions from the added acid to form the weak acid and a salt thereby removing the extra hydrogen ions from the solution and keeping the pH of the solution fairly constant. On the other hand, if a small quantity of a strong base is added to the buffer solution, the weak acid dissociates further to release hydrogen ions which then react with the hydroxide ions of the added base to form water and the conjugate base.
For example, if a small amount of strong acid is added to a buffer solution that is 0.700 M H3PO4 and 0.700 M KH2PO4, the following reaction is obtained:
KH₂PO₄ + H+ ----> K+ + H₃PO₄
Therefore, [H₃PO₄] will increase, [KH₂PO₄] will decrease, and pH will slightly decrease.:
Photosynthesis is where carbon dioxide and water through light energy is converted in glucose and other organic compounds.
Answer:
Dipole-dipole interactions
Step-by-step explanation:
Each molecule consists of <em>two different elements</em>.
Thus, each molecule has permanent <em>bond dipoles</em>.
The dipoles do not cancel, so the attractive forces are dipole-dipole attractions.
"Covalent bonds" is <em>wrong,</em> because there are no bonds between the two molecules.
There are dipole-induced dipole and London dispersion forces, but they are much weaker than the dipole-dipole attractions.
Answer:
Molality is 0.25 m
Explanation:
Molality → Moles of solute / kg of solvent
We need the moles of solute → 0.124 moles
22.4 g . 1 mol / 180 g = 0.124 moles
We need the mass of solvent in kg. We determine the mass of solvent with density.
Density = Mass / Volume
Mass = Density . volume → 1 g/mL . 500 mL = 500 g
If we convert the mass in g to kg → 500 g . 1kg / 1000 g = 0.5 kg
In conclussion, molality → 0.124 mol / 0.5 kg = 0.25 m
