This is a basic orbital diagram for carbon
I don’t know if this is right but I thing It’s B
Given:
A compound with:
Number of carbon atoms = 9
Number of double bonds = 1
A double bond between 5th and 6th carbon
A propyl group (CH2CH2CH3) branching off the 3rd carbon from the left
Try to illustrate the given and observe the formation of the atoms. Now, follow the correct IUPAC naming system. The name of the compound is
4-propyl-1-hexene
Count from the right to the left, the double bond is between the 1st and 2nd carbon, thus, 1-hexene. The propyl branches out the 4th carbon from the right, thus 4-propyl.
A reaction in which oxidation numbers change is the answer! :D
☆ Dont forget to mark brainliest ☆
Answer:
9 days, or 3 half-lives
Explanation:
5.2x10^5=520000
6.5x10^4=65000
65000/520000=1/8, or 3 half-lives
3x3=9 days
I'm not the greatest at Chem but this seems more like math than Chem :)
