Answer:
The molarity of a MnO4- solution
= 0.0342 M
Explanation:
Equation of reaction:
5Fe2 (aq) MnO4-(aq) 8H (aq) ---> 5Fe3 (aq) Mn2 (aq) 4H2O(l)
This is an example of redox titration.
Using titration formula:
CAVA/CBVA = NA/NB
where CA is the molarity of Fe2+ = (0.134 M)
CB is the molarity of MnO4- = (?????)
VA is the volume of Fe2+ = (30mL)
VB is the volume of MnO4- =(23.5mL)
NA is the numeric coefficient of Fe2+ in the equation of reaction = ( 5 )
NB is the numeric coefficient of MnO4- in the equation of reaction =(1)
Substituting the values into the formula;
0.134×30/CB×23.5 = 5/1
Therefore CB = 0.134×30/23.5×5
= 0.0342 M
1. 45.0 L H2S ( 1 mol / 22.4 L) ( 3 mol O2 / 2 mol H2S ) ( 22.4 L / 1 mol ) = 67.5 L O2 needed
2.<span>s- sphere, holds 2; p- dun bell, holds 6; d- complex, holds 10; f- very complex, holds 14
3.</span>In an ionic bond, oppositely charged ions are held together by the electronic force of attraction that exists between oppositely charged particles. In the ionic compound, anions and cations are present in a ratio that causes the total charge on the compound to be zero. Sodium phosphide, Na3 P, has three sodium ions for each phosphide ion. This ratio insures a zero total charge given the charges on the two individual ions (Na = 1+, P = 3-).
Are you like suppose to mix them together? to get another element?
Answer:
Sorry I didn't understand your question
